curious

[brodykade]

What is space?

 

[lunatio_gordin]

The vacuum in which everything exists?

 

[brodykade]

What is the density of space?

 

[lunatio_gordin]

unknown. we can't see everything that exists, the light hasn't had time to reach us.

 

[nexium]

I don't think we know the density compared to water = 1. Likely it varys from 10E-30 to 10E-50 depending on where in the Universe, how we count vertual mass, where we draw the line between nebula and space and atmosphere and space and wether we allow any mass for photons, nuetinos, tacyons etc. Perhaps someone can make a better guess. Neil

 

[MBA_UIU]

Space is the area that exists between all mass. You could say that it is where nothing else is. Outer space is not empty and is not a complete vacuum. A true vacuum is the absence of any mass or matter and as far as we know there is no place in space that light, radiation, solar winds and gravity does not reach. Vacuum in itself is not a force, but the absence of any force. <br /><br />As far as we know right now the area of the known universe is measured at 176,714,586,764,425,869,663.52 light years (diameter = 15b radius =7.5 (7.5b*4piR^2) gives us the size of the sphere. <br /> <div class="Discussion_UserSignature"> <p><strong><font color="#0000ff"><br /><br /> <br /><img id="268587ce-7170-4b41-a87b-8cd443f9351a" src="http://sitelife.space.com/ver1.0/Content/images/store/6/8/268587ce-7170-4b41-a87b-8cd443f9351a.Large.jpg" alt="blog post photo" /><br /></font></strong></p> </div>

 

[MBA_UIU]

Actually space does not have a density when you consider that density is a physical property of mass and matter. Because space is the absence of mass, and matter, it can only be measured by volume. <div class="Discussion_UserSignature"> <p><strong><font color="#0000ff"><br /><br /> <br /><img id="268587ce-7170-4b41-a87b-8cd443f9351a" src="http://sitelife.space.com/ver1.0/Content/images/store/6/8/268587ce-7170-4b41-a87b-8cd443f9351a.Large.jpg" alt="blog post photo" /><br /></font></strong></p> </div>

 

[nexium]

Hi MBA: Your formula/arithmetic is wrong. The volume of a sphere = 13.7b times 13.7b times 13.7b times 4.19 cubic light years. The area of the surface of a sphere = 13.7b times 13.7b times 4 pi square light years. The diameter of the visable universe is now thought to be 27.4b light years down from 30b light year in the middle of the 20 th century. Typically, we express the answer in 3 or 4 significant numbers if the least accurate factor is iffy in the 3d significant digit. The volume is about 10E31 = 10.7 decillion cubic light years. Neil

 

[MBA_UIU]

I did write the problem incorrectly as it should just be 4piR^2 to find the area of sphere. Given the numbers you have I get R^2=187E18 for an answer to 4piR^2 of 235E19 <div class="Discussion_UserSignature"> <p><strong><font color="#0000ff"><br /><br /> <br /><img id="268587ce-7170-4b41-a87b-8cd443f9351a" src="http://sitelife.space.com/ver1.0/Content/images/store/6/8/268587ce-7170-4b41-a87b-8cd443f9351a.Large.jpg" alt="blog post photo" /><br /></font></strong></p> </div>

 

[MBA_UIU]

BTW I was only figuring the area, not the volume of the sphere. <div class="Discussion_UserSignature"> <p><strong><font color="#0000ff"><br /><br /> <br /><img id="268587ce-7170-4b41-a87b-8cd443f9351a" src="http://sitelife.space.com/ver1.0/Content/images/store/6/8/268587ce-7170-4b41-a87b-8cd443f9351a.Large.jpg" alt="blog post photo" /><br /></font></strong></p> </div>

 

[alokmohan]

Thats probably correct.