B
bigbrain
Guest
Spacechump wrote:<br />"For compairison the Earth is 149 million kilometers from the Sun. Thanks to the inverse square law: <br />131 million km = 0.8756797 AUs <br />1/(0.8756797)^2=1.30 times the sunlight of earth...an increase <br />Now Manhattan seems to get a decent amount of sun so I don't think your argument holds any water". <br /><br />I asked him: "Explain clearer, please".<br /><br />spacechump wrote:<br /><br />"The distance from the sun to the earth is 149 million kilometers and is defined as 1 Astronomical Unit. The conversion of 131 million kilometers to AUs is: <br /><br />(131,000,000) / (149,000,000) = .876 AUs <br /><br />The inverse square states the as you travel outward from a radiation source the luminosity falls off as the square of the distance from the object. So in this case the comet is closer to the sun. <br /><br />Therefore using the inverse square equation 1/d^2 where d is the distance in AUs you get 1.30 times the amount of sunlight at any given point on a surface". <br /><br />Telfrow wrote:<br />"A real bigbrain wouldn't need any further clarification". <br /><br />You have not understood the situation:<br /><br />The earth is 133 million kilometres from the comet, not the sun. Why have you made those calculations?<br /><br /><br /><br /><br /><br /><br /><br /><br /><br />