drstein":31bj4jv7 said:

I think, when matter reaches the event horizont, matter gets to be so unstable so the structure of the atom breaks apart and particles that can pass the event horizon passes true the others just turns into light, as quazars do, they are the brightest stuff in the universe.

PS:

When we reatch the speed of light i think the same thing happends like near a black hole, and the mass increases too, so maybe we become a black hole directly... Im not sure about that. But this is what i belive!

To the best of my knowledge there's nothing that suggests atoms break apart at the event horizon. As a matter of fact, as I said above, an observer falling into a black hole won't notice anything especially unusual at the event horizon. The gravity will be strong, but not qualitatively stronger than just outside the horizon. Features of the horizon - like the fact that light can't escape - aren't things that would really affect us. Certainly nothing would turn into light (which is probably impossible in general relativity), and quasars are bright because of the disk of matter surrounding the black hole, nothing to do with the horizon.

Anyway, as for my last post...

I don't have time to run the math all the way through (since I do have actual work to do), but here's the basic idea: the time measured by the infalling observer is the proper time tau, while the time measured by an observer at rest (or at r=infinity, since the black hole spacetime is flat at large distances) is the time t. There's nothing weird about tau, you can calculate it to find out how long the infalling observer thinks it takes him to fall in, but as he approaches the horizon,

*t* goes to infinity, so the observer at rest will never see him enter. In the real world, though, there is no r=infinity, so there are no observers strictly at rest, and the time they measure on the falling guy's clock isn't exactly t.

So the idea that an outside observer doesn't see someone cross the event horizon is an approximation - true to an extent, but after a while it's no longer true.

EDIT: I'm actually not sure about that - someone correct me if I'm wrong

The observer's light cones do close up at the Schwarzschild radius so I suppose one would never actually see the crossing, just see the photons eventually stop coming.