Mechanical Electric Theory

sinkarma86 · Sep 18, 2008

http://academia.wikia.com/wiki/Mechanical_Electric_Theory [hide]<ul><li class="toclevel-1">1 Relations between energy, power, torque, distance, velocity, radius etc. </li><li class="toclevel-1">2 Voltage drops vs. Behavior and effects of distributed charge, mass <ul><li class="toclevel-2">2.1 Voltage drops </li><li class="toclevel-2">2.2 Behavior of distributed mass </li><li class="toclevel-2">2.3 Behavior of distributed charge <ul><li class="toclevel-3">2.3.1 Effect on real power (heat dissipation) </li></ul></li></ul></li><li class="toclevel-1">3 Assumption that capacitive voltage drop is fundamentally equivalent to applied voltage </li><li class="toclevel-1">4 Tenets of Mechanical Electric Theory <ul><li class="toclevel-2">4.1 Givens: </li><li class="toclevel-2">4.2 Result #1: Greater inductance for a given resistance increases torque output (angular momentum per unit time) vs. dissipated heat (energy per unit time). </li><li class="toclevel-2">4.3 Result #2: The L/R time constant determines the ratio of mechanical power to rate change in power. </li><li class="toclevel-2">4.4 Result #3: The ratio of mechanical power to dissipated heat is proportional to change in angle. </li><li class="toclevel-2">4.5 Result #4: To do a certain amount of work, the power must increase at a rate proportional to the square of the needed power. </li><li class="toclevel-2">4.6 Result #5: Electromagnetic radiation increases with the square of charge acceleration </li><li class="toclevel-2">4.7 Result #6: Torque produced by electrical energy increases with the power factor </li><li class="toclevel-2">4.8 Result #7: Efficiency of converting electrical energy into mechanical energy increases with the RC time constant and the angular velocity. </li><li class="toclevel-2">4.9 Result #8: Mechanical energy transfer divided by electrical energy transfer equals frequency of rotation divided by cutoff frequency. </li><li class="toclevel-2">4.10 Result #9: Apparent power is the product of electrical energy times angular velocity </li><li class="toclevel-2">4.11 Result #10: The ratio of mechanical energy to electrical energy is resistance^2 * capacitance / inductance </li><li class="toclevel-2">4.12 Result #11: Net acceleration results in an acceleration vector that is parallel to the radius of curvature. </li><li class="toclevel-2">4.13 Result #12: Angular velocity increases as the L/R time constant decreases. </li><li class="toclevel-2">4.14 Result #13: Mechanical power delivered for a given energy in transit is inversely proportional to the RC time constant. <ul><li class="toclevel-3">4.14.1 Refer to Result #11 </li></ul></li><li class="toclevel-2">4.15 Result #14: Mechanical power / apparent power = i </li></ul></li></ul>Mechanical Electric Theory (as of 00:24, 19 September 2008)== Relations between energy, power, torque, distance, velocity, radius etc. ==: force=energy/distance : force=power/velocity : force=(change of power/change of time)/acceleration: energy/power=distance/velocity : power/(change of power/change of time)=velocity/acceleration: torque=(change of angular momentum/time) : torque=force*radius : force=(change of angular momentum/time)/radius: energy/(change of angular momentum/time)=distance/radius=angle : power/(change of angular momentum/time)=velocity/radius=angular velocity: energy/power=angle/angular velocity : power/(change of power/change in time)=angular velocity/angular acceleration == Voltage drops vs. Behavior and effects of distributed charge, mass == === Voltage drops ===:''Applied voltage='' : Capacitive voltage drop : +Resistive voltage drop : +Inductive voltage drop :''Capacitive voltage drop='' : (1/capacitance)*charge :''Resistive voltage drop='' : resistance*current :''Inductive voltage drop='' : inductance*(change of current/change of time)=== Behavior of distributed mass ===: linear mass density=distributed mass/distance of distribution: linear mass density*velocity=mass flow rate : linear mass density*velocity^2=force : linear mass density*velocity^3=power=== Behavior of distributed charge ===: linear charge density=(charge/mass)*linear mass density:''Capacitive voltage drop='' : (1/capacitance)*linear charge density*distance:''Resistive voltage drop='' : resistance*linear charge density*velocity:''Inductive voltage drop='' : inductance*linear charge density*acceleration==== Effect on real power (heat dissipation) ====: resistive voltage drop=resistance*(charge/mass)*mass flow rate : real power=resistance*(charge/mass)^2*mass flow rate^2== Assumption that capacitive voltage drop is fundamentally equivalent to applied voltage ==: If capacitive voltage drop=applied voltage: :: resistive voltage drop= -inductive voltage drop :: resistance*current= -inductance*(change of current/change in time) :: resistance*current/linear charge density= -inductance*(change of current/change in time)/linear charge density :: resistance*velocity= -inductance*acceleration :: inductance/resistance= -velocity/acceleration== Tenets of Mechanical Electric Theory  ===== Givens: ===* The theory assumes that batteries supply voltage via a capactive voltage drop and that inductive and resistive voltage drops have the same magnitude but opposite polarity. * The theory assumes that Kirchoff's Circuit Laws and the Law of Conservation of Energy, Conservation of Angular Momentum, and Conservation of Momentum are basically true. * The theory assumes that what is determined in this theory is strictly deduced from the formulas of conventional theory, yet it insists that those same equations strictly lead to an area that is beyond the conventional understanding. * The theory assumes that mechanical energy and electrical energy are to be held as separate concepts.# '''Assumption that capacitive voltage drop is fundamentally equivalent to applied voltage''' :# capacitive voltage drop=applied voltage=voltage :# inductive voltage drop= -resistive voltage drop :# inductance/resistance= -velocity/acceleration # real power=resistance*current^2=power of dissipated heat # apparent power=voltage*current # torque=magnetic flux*current # torque=inductance*current^2 # electrical energy=voltage*charge # energy=torque*angle=mechanical energy=== Result #1: Greater inductance for a given resistance increases torque output (angular momentum per unit time) vs. dissipated heat (energy per unit time). ===: apparent power/torque=voltage/magnetic flux : apparent power/torque=voltage/[current*inductance] : torque=apparent power*[current*inductance/voltage] : torque=[real power/power factor]*[current*inductance/voltage] : torque=[real power/[current*resistance/voltage]]*[current*inductance/voltage] : torque=[real power*[voltage/[current*resistance]]*[current*inductance/voltage] : torque=real power*[inductance/resistance]=== Result #2: The L/R time constant determines the ratio of mechanical power to rate change in power. ===: inductance/resistance=torque/real power : inductance/resistance= -velocity/acceleration : inductance/resistance= -power/(change in power/change in time)=== Result #3: The ratio of mechanical power to dissipated heat is proportional to change in angle. ===: torque/real power= -velocity/acceleration : torque/real power= -momentum/force : torque*[ -force/momentum]=real power : [power/angular velocity]*[ -power/velocity]/momentum=real power : power^2/real power=angular velocity* -velocity*momentum : power^2/real power=[velocity/radius]* -velocity*[mass*velocity] : power^2/real power=mass*[ -velocity^3/radius] : real power*mass*[ -velocity^3/radius]=power^2 : real power*mass*[ -velocity^3/radius]=power*[linear mass density*velocity^3] : real power*mass*[ -velocity^3/radius]=power*[mass*velocity^3/distance] : power=real power* -distance/radius : power=real power* -angle : power/real power= -angle : power/real power= -distance/radius : power/real power= -energy/torque : torque/real power= -energy/power : torque/real power= -distance/velocity=== Result #4: To do a certain amount of work, the power must increase at a rate proportional to the square of the needed power. ===: -velocity/acceleration=-distance/velocity : velocity/acceleration=distance/velocity : velocity^2=distance*acceleration : force^2*velocity^2=force^2*distance*acceleration : power^2=energy*(change in power/change in time)=== Result #5: Electromagnetic radiation increases with the square of charge acceleration ===: real power/torque= -acceleration/velocity : real power= -torque*acceleration/velocity : real power= -mass*acceleration^2*radius/velocity: power=real power* -angle : power=[ -mass*acceleration^2*radius/velocity]* -angle : power=[ -mass*acceleration^2*radius/velocity]* -[distance/radius] : power=mass*acceleration^2*distance/velocity=== Result #6: Torque produced by electrical energy increases with the power factor ===: electrical energy/torque= : [voltage*charge]/[magnetic flux*current]= : [voltage*distance]/[magnetic flux*velocity]= : [voltage*energy]/[magnetic flux*power]= : [voltage*torque*angle]/[magnetic flux*power]= : [voltage*current*angle]/[power]= : [apparent power*angle]/[power]= : [apparent power*angle]/[-real power*angle]= : -1/power factor=== Result #7: Efficiency of converting electrical energy into mechanical energy increases with the RC time constant and the angular velocity. ===: electrical energy/torque=-1/power factor : electrical energy/[torque*angle]=-1/[angle*power factor] : electrical energy/energy=-1/[angle*power factor] : electrical energy*power factor=-energy/angle : [voltage*charge]*[resistance*current/voltage]=-energy/angle : [charge]*[resistance*current]=-energy/angle : [charge]*[resistance*current]=-energy/[distance/radius] : [charge]*[resistance*current]*[distance/radius]=-energy : resistance*linear charge density^2*distance*velocity*[distance/radius]=-energy : resistance*charge^2*velocity/radius=-energy : resistance*charge^2*angular velocity=-energy : resistance*charge*charge*voltage/voltage*angular velocity=-energy : resistance*(charge/voltage)*(charge*voltage)*angular velocity=-energy : resistance*capacitance*(charge*voltage)*angular velocity=-energy : RC time constant*electrical energy*angular velocity=-energy : RC time constant*angular velocity=-energy/electrical energy=== Result #8: Mechanical energy transfer divided by electrical energy transfer equals frequency of rotation divided by cutoff frequency. ===: RC time constant*angular velocity=-energy/electrical energy : 1/(2pi*cutoff frequency)*(turns*2pi/time)=-energy/electrical energy : 1/(cutoff frequency)*(turns/time)=-energy/electrical energy : (turns/time)/(cutoff frequency)=-energy/electrical energy=== Result #9: Apparent power is the product of electrical energy times angular velocity ===: RC time constant*angular velocity=-energy/electrical energy : RC time constant=(-energy/electrical energy)/(angular velocity) : RC time constant=(-energy/electrical energy)/(velocity/distance) : RC time constant=(-energy/electrical energy)/(current/charge) : RC time constant=(-energy/voltage)/(current) : RC time constant=-energy/apparent power : apparent power=electrical energy*angular velocity=== Result #10: The ratio of mechanical energy to electrical energy is resistance^2 * capacitance / inductance ===: inductance/resistance=torque/real power : L/R time constant=torque/real power : (L/R time constant)/(RC time constant)=(inductance/resistance)/(resistance*capacitance) : (L/R time constant)/(RC time constant)=(torque/real power)/(-energy/apparent power) : (L/R time constant)/(RC time constant)=-1/(power factor*angle) : (L/R time constant)/(RC time constant)=electrical energy/energy: RC time constant=-energy/apparent power: (L/R time constant)*apparent power/energy=-electrical energy/energy : (L/R time constant)*apparent power=-electrical energy : (L/R time constant)=-electrical energy/apparent power: apparent power=electrical energy*angular velocity: L/R time constant=(-1/angular velocity): (L/R time constant)*angular velocity=-1 : (-velocity/acceleration)*angular velocity=-1 : (velocity/acceleration)*(velocity/radius)=1 : velocity^2=acceleration*radius=== Result #11: Net acceleration results in an acceleration vector that is parallel to the radius of curvature. ===: velocity^2=acceleration*radius : velocity^2=acceleration*distance : radius=distance=== Result #12: Angular velocity increases as the L/R time constant decreases. ===: velocity/radius=velocity/distance : angular velocity=-resistance/inductance : (L/R time constant)*angular velocity=-1=== Result #13: Mechanical power delivered for a given energy in transit is inversely proportional to the RC time constant. ===: (L/R time constant)*(velocity/radius)=-1 : (RC time constant)*(velocity/radius)=energy/electrical energy : (RC time constant)*(velocity/radius)=-1/[angle*power factor] : (RC time constant)*(velocity/radius)=-1/[(distance/radius)*power factor] : (RC time constant)*(velocity/radius)*(distance/radius)=-1/[power factor] ==== Refer to Result #11 ====:'''Where: radius=distance''' : (RC time constant)*(velocity/radius)=-1/power factor : (RC time constant)*angular velocity=-1/power factor : (RC time constant)*angular velocity=electrical energy/torque : (RC time constant)*power=electrical energy=== Result #14: Mechanical power / apparent power = i ===: (RC time constant)*(power/voltage)=electrical energy/voltage : (RC time constant)*(power/voltage)=electrical energy/(charge/capacitance) : (RC time constant)*(power/voltage)*charge=electrical energy*capacitance : (resistance/voltage)*power*charge=electrical energy : (resistance/voltage)*power=voltage : (power factor/current)*power=voltage : ((-torque/electrical energy)/current)*power=voltage : (-torque/current)*power=voltage^2*charge : (-magnetic flux)*power=voltage^2*charge : (-magnetic flux)*power=electrical energy*voltage : -power=electrical energy*(voltage/magnetic flux) : (L/R time constant)*(angular velocity)*power=electrical energy*(voltage/magnetic flux) : (L/R time constant)*(angular velocity)*power=electrical energy*(apparent power/torque) : power^2=electrical energy*apparent power/(L/R time constant) : power^2=electrical energy*apparent power/(-electrical energy/apparent power) : power^2=-apparent power^2 <div class="Discussion_UserSignature"> </div>

coeptus · Sep 18, 2008

I believe this is the longest post of this 'special variety' to have not used the word 'tetrahedral'.     <div class="Discussion_UserSignature"> If not for bad Pluck, I'd have no Pluck at all . . . This is your vogon, posting under coeptus, and trying IE and Firefox to see if either is faster with fewer misloads. Erf !! </div>

emperor_of_localgroup · Sep 19, 2008

Replying to: <DIV CLASS='Discussion_PostQuote'>http://academia.wikia.com/wiki/Mechanical_Electric_TheoryPosted by sinkarma86</DIV>I hope this is not one of those post where the poster disappear forever after the first post when we need more clarifications.Would you please separate   'your' own NEW  theory (or equations)  from the  already established formula  and we use everyday?  To many formulae are copied from standard electro-mechanical books.   <div class="Discussion_UserSignature"> Earth is Boring </div>

DrRocket · Sep 19, 2008

Replying to: <DIV CLASS='Discussion_PostQuote'>I hope this is not one of those post where the poster disappear forever after the first post when we need more clarifications.Would you please separate   'your' own NEW  theory (or equations)  from the  already established formula  and we use everyday?  To many formulae are copied from standard electro-mechanical books.   Posted by emperor_of_localgroup</DIV>That post and the Wiki reference make no sense whatever.  It seems to be a mixture of a few standard relations, much that is gibberish or taken completely out of context and an equal amount that is patently false.  "Clarification" of that mess would take about 4 semesters of electrical engineering. <div class="Discussion_UserSignature"> </div>

MeteorWayne · Sep 19, 2008

Replying to: <DIV CLASS='Discussion_PostQuote'>That post and the Wiki reference make no sense whatever.  It seems to be a mixture of a few standard relations, much that is gibberish or taken completely out of context and an equal amount that is patently false.  "Clarification" of that mess would take about 4 semesters of electrical engineering. Posted by DrRocket</DIV> Considering the Raelian avatar, it's raelly ( />> ) not surprising that it's gibberish... <div class="Discussion_UserSignature"> But the Krell forgot one thing John. Monsters. Monsters from the Id. I really, really, really, really miss the "first unread post" function </div>

Mee_n_Mac · Sep 19, 2008

At least this time Kmar isn't telling us how to properly tax the worlds population. <div class="Discussion_UserSignature"> -----------------------------------------------------Ask not what your Forum Software can do do on you,Ask it to, please for the love of all that's Holy, STOP ! </div>

derekmcd · Sep 19, 2008

Replying to: <DIV CLASS='Discussion_PostQuote'>I hope this is not one of those post where the poster disappear forever after the first post when we need more clarifications.Would you please separate   'your' own NEW  theory (or equations)  from the  already established formula  and we use everyday?  To many formulae are copied from standard electro-mechanical books.   Posted by emperor_of_localgroup</DIV>Kmarinas has actually been around SDC for a long time.  Although, I'm a little mystified by this post... normally, he's a bit more coherent.  <div class="Discussion_UserSignature"> <div> </div> <div>"If something's hard to do, then it's not worth doing." - Homer Simpson</div> </div>

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