Scientists await signal from NASA's Parker Solar Probe after historic close sun flyby. Will it phone home?

Sep 24, 2024
15
0
10
At 430,000 mph, it could make a trip from Earth to Mars in under 4 days. It makes you realize that if there is any "barrier" for humans to make a trip to Mars, it probably the speed of the spacecraft.
 
Apr 18, 2020
145
28
4,610
At 430,000 mph, it could make a trip from Earth to Mars in under 4 days. It makes you realize that if there is any "barrier" for humans to make a trip to Mars, it probably the speed of the spacecraft.
No, the limit is the endurance of the human body in the conditions produced by the trip. How do you get to 400,000 mph?
 
Sep 24, 2024
15
0
10
No, the limit is the endurance of the human body in the conditions produced by the trip. How do you get to 400,000 mph?
Start with our current speed to the Moon at 5,000 mph and start improving on it. A point of the article is that a spacecraft made it to a speed that would easily overcome the distance to Mars. It invites us to think about improving our speed for voyages in the solar system.
 
Feb 14, 2020
253
62
10,760
Historic Milestone 3.8M miles from Surface of Sun – NASA Solar Parker Probe Launched in

2018,

Dr. Ravi Sharma, NASA Apollo Achievement Award 1969



Some of my NASA and Space industry colleagues are capable of outlining several technologies that would accelerate from translunar or escape velocity trajectories to 400k mph with safe human tolerable acceleration levels as well as decelerations for surface landings. Perhaps these would include Powerful Nuclear fusion (fission / Thorium) Propulsion or ion engines?



Thanks to Tariq Malik Editor for yet another valuable Space.com post on this Parker Solar Probe. What we also need from Space.com or other preprint servers like arXiv is a running status and progress report for semitechnical audiences as well that includes discoveries or phenomena on our star and its heliosphere recorded by Parker, Aditya, Chandra, JWST, European probes and other Observatories, especially including synchronization, verification and CME, Solar Activities, impact on ionosphere, Space assets and terrestrial grids etc.



Coming back, description of plasma and ionized matter as classical thermodynamic entities is often misleading. Temperature makes sense when there is stable enclosed configuration of phase of matter. Solar Corona thermodynamic parameters, even the Maxwell Boltzmann Distribution of Blackbody is an approximation rooted in Quantum and Field theoretic descriptions of these unique states of matter-energy. Magnetohydrodynamic surface phenomena ought to be only approximately described in terms of thermodynamics. Anisotropy, variety of re-combinations, radiation and radiative transfers as attempted by stellar and solar astrophysicists are all going to be helpful in interpreting these new data that are challenging our current understanding of the Sun.

Accelerating learning with hopefully beneficial AI would make such journeys to planets by humas possible at such speeds hopefully in the next hundred years!
 
Energy = 1/2 * m * v^2
The velocity after an 11 hour boost at 1 g is equal to 9.8 m/s times 39600 s.
Velocity equals 388,080 m/s

Assume a one kilogram mass.
Energy = 1/2 * 1 kg * (388,080)^2 = 7.5e10 Joules
570 gallons of gasoline
 
Apr 18, 2020
145
28
4,610
Energy = 1/2 * m * v^2
The velocity after an 11 hour boost at 1 g is equal to 9.8 m/s times 39600 s.
Velocity equals 388,080 m/s

Assume a one kilogram mass.
Energy = 1/2 * 1 kg * (388,080)^2 = 7.5e10 Joules
570 gallons of gasoline
Looks like a tradeoff between how much fuel you can carry and how long you want the astronauts to be traveling.
 
Jan 28, 2023
294
46
1,710
I'll stand corrected. So 5½ hours @ 1g up to speed, and another 5½ @ 1g to stop. But what about the energy requirements for accelerating the mass of a suitable spacecraft for 11 hours @ 1g?
Yes if you start to your destination from zero relative speed to target and need to decelerating to zero before landing. The colleague's calculations are conditionally accurate* under these specific conditions and if the spacecraft is single-stage. If you want accurate calculations from launch from the Earth's surface to the moment a spacecraft lands (say on Mars) then you need several significantly more complex equations with many more parameters involved.
Energy = 1/2 * m * v^2
The velocity after an 11 hour boost at 1 g is equal to 9.8 m/s times 39600 s.
Velocity equals 388,080 m/s

Assume a one kilogram mass.
Energy = 1/2 * 1 kg * (388,080)^2 = 7.5e10 Joules
570 gallons of gasoline


*There is a formula that takes into account the decreasing mass of a spacecraft due to the gradual ejection of fuel and oxidizer in the form of exhaust gases while the engines are operating. In addition, dry mass can also be ejected in the form of spent stages and shields of the spacecraft. The arriving spacecraft already has a lower mass when it reaches the part of the trajectory where it begins to slow down.
Then we can talk about why the speed is not reduced to zero relative to the planet reached before the landing phase begins. Because it is more difficult and less economical. Also, if the planet has an atmosphere, aerodynamic deceleration can be used, which also saves fuel.
 
Yes, the mass decreases as the reaction mass is ejected.
To get one kilogram to the desired velocity requires more energy than my simple calculation shows.
For launches to LEO, about 5% of the launch pad mass gets there.
Multiply my number by 20.
 
  • Like
Reactions: George²

Latest posts