S
Solifugae
Guest
How much energy is there keeping all of the stars and material together in the Milky Way? Or in other words, if the Daleks wanted to destroy it with a giant interdimensional extinction bomb, how much yield would it have to be packing? (and we're ignoring the fact that the central blackhole would soak most of it up.)
I don't know "math language" so I couldn't use the GBE formula cited on wikipedia. I tried a simple layman terms approximation just using the known parameters...
Assumed stars with mass of the sun (1.98892e+30 kilograms). They need to be accelerated to greater than 1000km/s to escape (but this figure is for our solar system's distance from the center, so it doesn't account for the much greater velocities needed for objects near the center).
This requires 9.945E+41 joules of relativistic kinetic energy for the sun.
The sun has a cross sectional area of 3.04385e+18 meters (half its surface area), and the sphere area of the 100,000 light year Milky Way Galaxy is
31,415,926,535 light years.
Therefore, the energy applied per square light year is 3.12431389e+52 joules.
However we still need to apply enough energy per the area that stars would reside in, so we need the difference between the sun and the sphere, which is 97,643,203.5, and we times the previous figure showing the amount of joules to get the required amount of energy per every area of the sphere that equals the area of the sun.
Gravitational Binding Energy: >3.05068017e+60 joules
This is 76.2670042 times the visible total mass-energy, and 30.5068017 times the total mass-energy estimate which includes dark matter and dark energy (You can find this cited on wikipedia).
So, have I gone wrong anywhere? I sort of doubt this has ever been calculated before, due to impossibility of occurrence in nature.
I don't know "math language" so I couldn't use the GBE formula cited on wikipedia. I tried a simple layman terms approximation just using the known parameters...
Assumed stars with mass of the sun (1.98892e+30 kilograms). They need to be accelerated to greater than 1000km/s to escape (but this figure is for our solar system's distance from the center, so it doesn't account for the much greater velocities needed for objects near the center).
This requires 9.945E+41 joules of relativistic kinetic energy for the sun.
The sun has a cross sectional area of 3.04385e+18 meters (half its surface area), and the sphere area of the 100,000 light year Milky Way Galaxy is
31,415,926,535 light years.
Therefore, the energy applied per square light year is 3.12431389e+52 joules.
However we still need to apply enough energy per the area that stars would reside in, so we need the difference between the sun and the sphere, which is 97,643,203.5, and we times the previous figure showing the amount of joules to get the required amount of energy per every area of the sphere that equals the area of the sun.
Gravitational Binding Energy: >3.05068017e+60 joules
This is 76.2670042 times the visible total mass-energy, and 30.5068017 times the total mass-energy estimate which includes dark matter and dark energy (You can find this cited on wikipedia).
So, have I gone wrong anywhere? I sort of doubt this has ever been calculated before, due to impossibility of occurrence in nature.