Recent content by RogergR

Sub-question Is it true that if you observe Jupiter and its moons with a gadget that allows you to see at most 4 of these, you see only 3 on average.

Easy, becouse you miscalculated cose your pictures are wrong. Sry for the ugly picture this is the field view for one month. Beter picture the midle sized circle area is the one month perpendiculary. However. In terms of space. The area of the earth is simplified 4π6378^2. And the area that...

If you make a one month timelaps perpendicular to the Moon-Earth system, the earth will cover (6378km+4671km)(6378km+4671km)π of the picture. If you make a similar timelaps from the field of M-E, the area will be (6378km x 6378km) π + (4671km + 4671km) x (6378km + 6378km). The second, field...

Look, if you follow this thread and can not get to this numbers by yourself....like I said, pls dont troll anymore.

But can you tell me how much is this "slight wobble" involved? I can tell you how big is that "wobbleing", easy maths. In terms of perpendicular to the system we get a circle area which is 3 times larger than 2D earths area, and in terms of horizontal (ecliptic) view of the system we get an...

Snowflakes in this case are not usefuly random. Falling objects in the direction earth-moon are atracted by gravity, and the baricenter of earthmoon is the center where they are "targeting", if we ignore the sun, the other planets and moons and the nonvacuum at all interspace.

Thank you a lot for the research :).... I still think that there is even more Moon protection....and, planets with moons are beter for life in general.

Your tennis ball is static, in the system earth-moon also the earth spins around the baricenter.

I said imagine ideal conditions. If you have a vacuum space and in it only 3 equal 1 cm large stationary ideal balls where the first weighs 10 kg and touches the second which weighs 1 kg and the third at a distance of one meter weighs 1 gram, equidistant from the first two when time starts ...

Objects are not falling to earth but to the system moon-earth, so we have 2 pendulums at the same time. ..4700 km is the circle of barycenter, thats the target for gravitationaly falling objects, not the center of earth. Imagine We have space, gravity, a stacionary moon and earth and an object...

I disagree with you Barycenter Earth-Moon :cool: Let's do a simple calculation. Imagine that the moon does not exist and an object goes towards the earth perpendicular to the ecliptic with an accuracy of lets say 1111 km to hit it in the middle. This is a 2D model, for simplicity, so...

Probably somebody should do a simulation, to get a tangible result.

My point is that objects with random trajectories are targeting the mass center which is not the center of the earth, but the center of the system earth-moon in this case.

The bigest target (you call it barrier) is however the sun, but objects evaporize before they hit it. I was hoping to find a link here to some calculations, a solution maybe or something like that as far as just the earth and the moon are concerned.

The answer is simple. The heavier one. Neutron stars have masses between 1 and 2 solar masses, and the smallest known black hole has 6 solar masses, but we will probably find a smaller one. Acording to "sience" there are also micro black holes, so...