The Earth is spinning about the axis which joins the North and South poles. Obviously the angular velocity is the same for all latitudes, viz. 360 degrees per day. (note that this is not the case on Jupiter or the Sun).<br /><br />Now although the angular velocity is the same for all latitudes, the tangential velocity varies. Standing "still" on the equator, in one day you travel a distance equal to 2 * pi * (radius of earth), while at the north pole you travel no distance at all in the same period of time. <br /><br />Therefore, tangential velocity is greatest at the equator and decreases as you go further north. In fact it is proportional to the cosine of your latitude.<br /><br />Now, imagine that you are standing on the equator and you fire a cannonball northwards. Disregard the atmosphere, and we are not interested in the vertical velocity of the cannonball i.e. its altitude.<br />When the ball leaves the cannon it carries a full 460m/s of tangential velocity, going eastwards since the earth rotates from west to east. This is in addition to the northwards velocity which we have given it from the cannon.<br /><br />Time passes, and the ball impacts some distance to the north. During the flight it had a constant 460m/s eastward velocity so in absolute terms (if the Earth had not been spinning) it has moved a considerable distance to the east. But of course the Earth is spinning, so the land on the impact site has been moving eastwards too. HOWEVER, because the impact site is north of the equator, it does not have such a great eastwards velocity as was explained earlier. For example if the impact site is at 20 degree latitude, the eastwards velocity of the surface there is 460 * cos(20) = 432 m/s. So the land hasn't moved so far east as the ball. Therefore, the ball appears to land somewhere to the EAST of the direction it was fired in. For someone in the rotating reference frame of the Earth, there appears to be a mysterious force pushing it eastwards.<br />