<p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Black holes are just another manmade construct as is the theory of evellution.</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">This theory makes more sense:</font></p><font face="Calibri"> </font><font face="Calibri"><span> </span>THEORY OF EVERYTHING</font><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">This theory was created in 1970 and has been consistently supported by new discoveries in Particle physics and cosmology. </font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">In the beginning, there was a naked singularity, which I call the JAH Field. The JAH Field is composed of JAH's in a density calculated by Bechtel's Perfect Cube, the seminal equation of this theory.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>BECHTEL'S<span> </span>PERFECT<span> </span>CUBE</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>The cube root of 10>-50ccm //10>50JAH</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">This cube root quotient is equal to the absolute value of the Plank length, 10>-33 1/3cm.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Therefore, for every 10>-50ccm of space there are 10>50JAH, and each JAH has a diameter of 10>-33cm.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Each JAH spins at the rate of: w=X/pD, where D=the JAH diameter, p=Pi and w=Rho.// equal a division sign.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Then, w = 2.998x10>8 m/s//px10>-331/3cm</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>w = JAH spin = 9.54x10>42 1/3Hz.</font></p><font face="Calibri"> </font><font face="Calibri"> </font><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Because each JAH has equal spin, its True Energy = EE = Plank constant //f= 6.625x10>-4J.s//9.54x10>42 1/3s</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">EEJAH = 6.949x10>-77 1/3 J.</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"> </p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The electron volt equivalent = h//J/eV </font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The eV/JAH =<span> </span>6.649x10>-77 1/3J = 4.343x10>-58 1/3 eV/JAH </font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">=1.602x10>-19 J/eV</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The mass of each JAH = MeV/JAH x em // eMeV </font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">JAHm<span> </span>= 9.11x10>-31Kgx4.343x10>-52 1/3MeV// 5.11x10>6 MeV = 7.742x 10>-89 1/3Kg.</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Where<span> </span>em = 9.11 x 10>-31 Kg</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>eMeV = .511</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>JAHMeV = 4.331 x 10>-52 1/3 MeV</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>JAHm = 7.742x10>-89 1/3 Kg</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The number of JAH/e = 9.11x10>-31 Kg//7.742 x 10>-89 1/3 Kg = 1.1766x10>58 1/3 JAH/e = 11766 x 10>54 1/3 JAH/e</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The 1/3 power of<span> </span>JAH's/e = (11766x10>54)>1/3 = 22.745x10>18 JAH/e, therefore the 22x10>18 JAH are added to the 11766x10>54 JAH/e and the<span> </span>eV binding EE =.745 x 10>18 JAH/e x 4.343x10>-58 1/3 eV/JAH = 3.2355 x 10>-40 1/3 eV.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">This 3.2355x10>-40 1/3 eV<span> </span>is the True Energy that binds the JAH's into a relative particle of matter and is equal to the total relative strong force within the electron.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The difference between EJA Hm and EEJA Hm =[E=Mc2] therefore =<span> </span>(7.742x 10>-89 Kg +4.297x10>-71 Kg)(2.988x10>8 m/s)>2.</font></p><font face="Calibri"> </font><font face="Calibri"> </font><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">EJA Hm = (6.9585x10>-72 Kgm>2/s)>2 = 6.9585x10>-72 J.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The electromagnet spectrum runs from 6.625 x 10>-34 Js to 137 x 6.625 x10>-34 Js therefore EJA Hmax = 9.076x10>-32 Js.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">There are 137 prime relative gradations in the EEJAH spectrum.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">137x6.625x10>-34 Js = 9.076x10>-32 Js at alpha = 90 degrees.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>100 x 6.625 x 10>-34 Js at alpha = 100 degrees</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>45x6.625x 10>-34 Js at alpha = 45 degrees.</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span><span> </span>2 x 6.625 x 10>-34 Js at alpha = 2 degrees</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><span><font face="Calibri"> </font></span></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>6.625 x 10-34 Js at alpha = 0 degrees.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">This set of absolute values is restricted to four significant figures by using the J/eV, eMeV values. </font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The Plank length is verified by BECHTEL'S PERFECT CUBE.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The two electrons in each sub-orbital then repel each other with twice this force and this keeps them separated in the sub-orbital. </font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The electrons magnetic moment<span> </span>precession, as it travels around the nucleus, causes them to follow a figure eight pattern due to the varying repulsive forces caused by the angles of moment of each electron. </font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">All particles are composed of three groups of resonating JAHs with up or down spins, which are bound by an area of combination and when they are separated by force, those areas momentarily create the six fragments called quarks and have either up, down,<span> </span>top, bottom, charm or beauty (intermediate) magnetic moments as well as the fragments called W+,W-,Gluons etc..</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Each JAH has equatorial velocity equal to c and moves the resonating groups of JAHs at that maximum velocity through the JAH Field, where all JAHs are stationary within the JAH Field. These equatorial circles have a diameter of the Plank Length and when seen sidways create strings with a diameter equal to the Plank Length.</font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"> </p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The absolute electron mass = eEEm = 1.766 x 10>58 1/3 JAH/e x 7.742 x 10>-89 1/3 Kg = 9.1092 x 10 >-31 1/3Kg.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">The absolute proton mass = PEEm<span> </span>= 1836 x 9.1092 x 10>-31 1/3 Kg = 1.67244 x 10>-27 Kg.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Mass of hydrogen = HEEm = 1.67244 x 10>-27 Kg + 9.1092 x 10>-31 1/3 = 1.6733 x10>-27 Kg </font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Some predictions of this theory are:</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>1. Galaxies reaching near light velocity at the edge of the universe disintegrate leaving gamma ray bursts<span> </span>and non-existent optical galaxy photons, solving the mystery of the missing galaxies.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri"><span> </span>2. Where such gamma ray bursts occur, the background radiation shows a slight increase relative to the average 3 degree MBR.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">3. That Black Holes are areas where gravity has been focused, eg. center of galaxy and the JAH Field is not able to resonate any groups of JAHs (matter) through the field, causing no transfer of light photons.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">4. That because the JAHs are stationary within the JAH Field, the </font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">Michelson-Morley<span> </span>experiment does not apply as a method of determining the JAH Field existence.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">5. That The General Theory of Relativity applies to the JAH Field but not the groups of<span> </span>JAHs (matter) within the field .</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">6. That Quantum Mechanics and Relativity can be married in this theory once the non-relative parts are excluded.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">7. That the bending of light in a magnetic field is caused by the </font></p><p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">local inability of JAHs to resonate matter through the field and not because there is a warping of the field or space-time.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">8. That the alleged missing matter in the universe is the Zero Point Field creations of hydrogen and virtual particles.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">9. That for the neutrons and neutrinos, the rotation of the particle group of JAHs is the reverse to that of the individual JAHs or have spherical shells of JAHs with reverse spin to the group and which will therefore not allow the particle to combine with other groups but will support Beta decay.</font></p><font face="Calibri"> </font> <p style="margin-top:0in;margin-left:0in;margin-right:0in" class="MsoNormal"><font face="Calibri">10. That there is only one true particle which is combined into groups(matter) and all others are fragments of groups. These fragments are unstable and disintegrate into the known fragments or cease to resonate as a group in the JAH Field.</font></p><font face="Calibri"> </font>