No, my point was that over time the charged wire should loose mass. But it doesnt. And once you remove the charge? Does this "missing" mass magically return? How can the wire possibly have the same mass if its loosing mass through electron flow? Shouldnt the wires eventually revert all to protons once the electrons and there mystery mass are used up?
No of course not......and why?
Energy can be converted to mass and vice versa, but energy does not "have" mass. E=MC2
An electron MAY have mass, but you cannot directly measure it, you can infer it, but If you could directly measure the mass of an electron, then you would know where that electron is. THATs a violation of the laws of physics.
All this means is that its not loosing anything. Electricity flows in a circuit. Unless you can demonstrate how mass fluctuates all throughout the circuit as the electrons flow.......(mass flowing through the circuit as well), then Im afraid that I just dont understand where this mass is. Its not in the power source, the battery should be LOOSING mass by using its electrons.
But thats not whats happening now is it.
The battery, through a chemical reaction, causes an electron to go from, say from one lead plate to another.
This electron travels out of the + terminal, and out through the circuit and re-enters the - terminal. This is called an electrical circuit. Without the return path, electrons DO NOT FLOW!
So, does the lead plate "loose" electrons?
No, it does not. What happens is that the chemical ELECTROLITE gets used up and converted to a gas. A highly EXPLOSIVE gas IIRC. If you remember the old car batteries, this fluid could be refilled. You would use a hydrometer (I think) to measure the fluid levels in each cell. Now what would the point be in refilling the liquid if the lead plate was spent and no longer had any electrons to pass to the next one? The circuit would be broken. For every electron that leaves the + side, an equal number of electrons enter the - side. No electrons lost, none gained. In the end, its all the same. The "loss" is the electrolite being converted from a liquid to a gas. As this happens it becomes harder and harder for electrons to pass between the plates. Once the liquid is gone, the battery is dead. Cells dry out and they begin to corrode, ruining the cells. Not even refilling at that point can save the battery.
The speed of electricity is limited to the conductor. A copper wire can get to about 96% the speed of light, with the remainder being due to the limitations of the conductor. A "perfect" conductor would propagate electricity at C. CO-ax cable goes even slower.
In a vacuum, like any other electromagnetic wave, its going at 186000 mps
You can slow light itself down with exotic materials, but does this now mean that light no longer travels at the speed of light?
Bottom line.....Electrons are NOT lost, the energy they carry IS. But the number of electrons stays the same. Copper doesn't mutate to a lower element due to the presence of an electric field, and then turn back into copper when the power is cut. If electrons were ripped off the molecules and "lost mass" then this would happen. At the least, every single atom should be ionized, and stay that way. But they are not. Not to mention you would only be able to use each wire once, as to exposure to the electric field would change its atomic structure, hence ruining the conductive qualities of said wire.
But again, nothing is lost. The electrons are "bumped" from one atom to the next through the "pressure" of voltage. Like the expansion of the Universe, taken all together from beginning to end its moving at about c. When you cut the power, all of the copper atoms have all of the electrons they are supposed to have. No mass is lost. And the wire is not Ionized copper, but plain old copper.
From atom to atom however, (or galaxy to galaxy) it appears to be moving much slower. Only when you look to the farthest point and measure its velocity does light speed, or near light speeds, become apparent.
Now dont get me wrong, enough voltage will melt any wire, but this is an entirely different phenomena then ionization. Enough heat will vaporize anything. This is not an "electric" reaction per say, they same effect can be had if I toss it in a fire.
So, atom to atom, sure. It goes slower, at least, theoretically.
But taken as a whole, its going close enough to light speed as to not matter. When you add an electron to one end of a conductor, and give it a little voltage, at the same time an electron pops out the other end of the conductor. This is why it is said electricity travels at the speed of light. Yes it is a cumulative effect I know, but the results are still the same. I connect a light bulb and apply some current and instantly the light bulb becomes illuminated.
And if you were taking a test in an electrical class and you were asked "How fast does electricity travel" and you answered something OTHER than 186000 mps you would get the question wrong.
As taught by the William J Dean Technical Vocational High School in Holyoke MA. Electrical Class 1986-1988
As taught by the Comprehensive High School in Chicopee Ma. Electrical Class 1989
(O and MW, I was looking over my old final exam, and guess what, I got the transformer question wrong there as well. :lol: )
(Still, out of 100 questions, 2 wrong. Ill take a 98 on a final any day of the week!!! The other one I got wrong was a circuit layout for a 3 wire return call system. The diagram was perfect except for one minor detail. I forgot to connect the circuit to the power source. So all my equipment connections were correct to each other.......but no power. oooooops :lol: :lol: :lol: :lol: :lol: :lol: :lol: :lol: )
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Now, with all that said, I graduated in 1989. Many things have changed since then, and I will research this because there is a reasonably good chance that my information is dated. New things are discovered every day, and I haven't been keeping up with my studies as well as I should, this I will admit.
So, all in all, I thank you for calling my attention to this possible oversight. I will read more into it, and hopefully come out of it a bit smarter than when I started. I'll look into it, and get back to you. Those equations you posted and the reference material should keep me busy for a bit. But I will concede that my information is old, and perhaps its time for a refresher.
TTFN
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