Ginjar":a1f23d1o said:
I am not sure of this but i was just wondering if it is possible. If a person is pulled past the event horizon of a black hole, the differences of the gravitational pull on opposite ends of the person is so great that the person would be pulled to look like "spaghetti." However what about the individual atoms that make up that person? Wouldn't gravity have a different effect on different parts of the atom? Gravity would pull certain electrons more than others, and therefore essentially pull the atom apart. If this is true than wouldn't a black hole have a different effect on more complex atoms, such as a helium atom being effected in a different way than an atom of iron?
Great question! I think this boils down to the following: is the graviational difference near the event horizon over the radius of an atom greater than the electrostatic attraction between the nucleus and the electrons. This calcuation can be a complete nightmare (for me at least) because there is no way to discount the warpage of space near the event horizon which means you would need to use general relativity. But you could use newtonian gravity for an first approximation.
The amount of energy needed to pull an electron from the atom can be found by the energy of a photon that causes the photo electric effect.
The difference in the gravity over the radius of the atom can easily be found using the 1/r^2 since the black hole would be a point source. The baseline gravitational force and distance from the blackhole would be calculated at the event horizon with the Schwarzschild radius. Again this is completely disregarding general relativity and assuming that the Schwarzschild radius is a straight line radius (which will throw in significant errors).
I don't have time to calculate this since I am at work and suppose to be working!