Recall that we're not feeling the gravity - we're seeing objects which are. Erm, I mean, I think it's possible we feel it too, but it's so minor as to be negligible here. Not sure.
To see the effect of the gravity before you see the light emitted from its source sounds problematic to me.
A----->B----->C
Let A be the source of gravity (unknown in the above paper)
Let B be the object being acted upon by A (hunderds, perhaps thousands of galaxies)
Let C be the observer (us)
If Gravity propagates at c then the image of A must reach B at the same time Right?
So.... If C (the observer) sees the action of A s gravitational field on B then A must also be visible to C because the observation comes to the observer at the speed of light..
The only way A is not visible to C and yet we observe A s gravitational influence on B is if gravity propagates faster than c.
Ce senior?
(not my prefered thought, but....)
Unless: 1) this observation is flawed, or 2)there is the possibility of a super duper truly humungous mother of all black holes, I would expect that A s region of space should be visible if the GR prediction of the speed at which gravity propagates = c stands solid.
This is a bit of a canundrum to me. Does anyone wish to pick an option? Is my reasoning pertaining to this sound?