I suppose it wouldn't be too easy, but angle between Polaris and point directly overhead would be accurate to a degree or so (assuming you figure directly overhead point accurately).<br /><br />Or subtract elevation of Polaris at your location from 90 degrees. It would be close.<br /><br /> <div class="Discussion_UserSignature"> <p><font color="#ff0000"><strong>TPTB went to Dallas and all I got was Plucked !!</strong></font></p><p><font color="#339966"><strong>So many people, so few recipes !!</strong></font></p><p><font color="#0000ff"><strong>Let's clean up this stinkhole !!</strong></font> </p> </div>