<font color="yellow">No, C3=0 means an escape trajectory, actually from the surface of the planet, for which a low (circular) orbit is a good approximation. As you say, it's a parabolic trajectory which, if you lower C3 just a little, becomes a highly elliptical orbit. </font><br /><br />Well, we're both abusing the term C3, I was just trying to go with the flow and reduce my pedantic tendencies a bit. And I think you're slightly misquoting me.<br /><br />C3 is realted to Vhyp = 'excess hyperbolic velocity', relative to the planet you're trying to escape.<br /><br />Vhyp = sqrt(2*C3)<br /><br />If C3 is even slightly negative, you will eventually come back cuz you didn't escape. If you have positive C3, you escape. 'C3=0' is a rather abstract mathematical concept in the real solar system.<br /><br />But a low circular orbit is NOT a good approx for C3=0. It has a lot of bound energy, but by definition C3=0 means zero bound energy. Also, if you say 'highly elliptical' that implies a low periapse, which means you're down in the gravity well a lot deeper than C3 = slightly less than parabolic. <div class="Discussion_UserSignature"> </div>