Good points...Lets discuss.<br /><br /> />>The length of the of the Dr Hugh Edwards' tether is almost 3 times the distance to geo stationary altitude with considerable ballast,....<br />With that much length, both the inner and outer planets are reachable without additional propultion, only course adjustment thrusters. The lunar elevator only allows access to solar orbit at L1 or Earth orbit. Both require additional propultion, which in the case of a STS sized launch system means about 3 million LBS of propellents to get to and land on Mars.<br /><br /><br /> />>Will the 5 degrees the moon orbit is tilted with respect to the plain of the Earth's orbit complicate the design? <<<br />I don't think so, the elevator will always point directly at Earth. As you point out later, the moon does have a rocking motion, that and the Earth gravity well can be used to add several Km/s to any payload. That is what I ment about using the Earth's gravity well to slingshot payloads.<br /><br /> />>The radius to the center of the moon is about 78,000 miles times 6.28 = the distance the end travels in 27 days = 18,142 miles per day = 756 miles per hour with respect to the moon's surface, at the Moon's poles.<<<br />No energy can be gained from the Moon's rotation because the same side always faces the Earth, so there isn't any rotational energy available for an elevator on the Earth's side of the Moon. An elevator on the far side would be able to sling payload very fast, but it would have to be very long to overcome the Moon's gravity.<br /><br /><br /> />>It may be practical to flip a space craft off the end, like the crack of a whip with the help of carefully timed transients. I think this is also true of the Dr Hugh Edwards' elevator. <<<br />While the Moon's elevator might be able to use the "crack of a whip" method, the Earth elevator uses centriapedal forces.<br /><br /><br /> />>2 Another problem with rotating tethers, is extremely critical timing of bo