Please do not take this as being critical of yourself. You impress me as a very well meaning person, and I like most of your posts and ideas!<br /><br />However, could I make one possible suggestion? Please get yourself some kind of general astronomy or space books and read them. As an example your post is very confusing, and if what you mean is what you apparently mean, then you don't really understand what a geostationary orbit is. Or perhaps if you do know, you (like I sometimes do also) misspoke yourself.<br /><br />A geostationary orbit is an orbit far enough out from a planet, moon or other substantial spherical body (one which has a reasonable gravity field) such that the velocity of the objects (satellite, space station, spacecraft, or other object much smaller than the orbited body), keeps the orbiting body at a stationary spot over the orbited body. This is a Very Important Orbit, as it allows orbiting objects such as communications satellites to “Hover" above one spot over the equator of the orbited body.<br /><br />Now, this orbit for the Earth is some 25,000 miles or 36,000 kilometers (approx) in altitude above the Earth's surface. Then for the moon with 1/6 th the gravitational force of the Earth, such a geostationary orbit would be 0.16 times 36,000 kilometers or some 6,000 kilometers above the moon's surface. Which would place the orbit's nearest approach to the Earth at about 385,000 kilometers minus 6,000 kilometers (average distances) or about 380,000 kilometers!<br /><br />Now this obviously would not place such an orbit into the center of the Earth. Am I clear here?<br /><br />Please understand that I am not being pedantic to an obviously intelligent poster such as yourself. What I am attempting to do is to perhaps clear up some confusion on your part here.<br /><br />It is my belief that these boards (particularly some forums such as M&L) are not just for debating subjects. These forums can also be used as a learning area. And I have also l