Need some help

[Catastrophe]

According to https://vixra.org/pdf/1103.0060v1.pdf

M is solar mass M, and h is angular momentum ML^2. u is orbital distance.

Cat

 

[Helio]

Here is a five year intensive study by Cornell University that shows that a partially liquid core plays a large role in (Mercury's) orbit.

I don't see that they address orbital relationships with cores. It is about spin. It's an interesting paper that shows Mercury likely formed much farther out then migrated inward. This is consistent with theories like the Grand Tack model where Jupiter migrated inward and wiped out the early planets, but then was pulled outward by Saturn, allowing new ones, fortunately for us, to form.

Core densities will alter their migration rate, in or out, due to angular momentum exchanges due to different rotation-revolution rates. But Mercury is tidally locked so I doubt there is much change in the orbit at this time.

Orbits and trajectories require energy or mass exchanges outside of itself. Spin is internal.

 

[Helio]

According to https://vixra.org/pdf/1103.0060v1.pdf

M is solar mass M, and h is angular momentum ML^2. u is orbital distance.

Cat

Wow. That's heavy duty!

Remember that to determine the angular momentum the mass of the body (ie Mercury) is required. So I would guess some mass value is needed for the equation, though a slight error may not have much effect as you note earlier.

 

[Catastrophe]

Wow. That's heavy duty!

Remember that to determine the angular momentum the mass of the body (ie Mercury) is required. So I would guess some mass value is needed for the equation, though a slight error may not have much effect as you note earlier.

Angular momentum is included as h? h= angular momentum in d²u/dφ² + u = GM/h² + (3GM/c²)u²

 

[Helio]

Yes. It’s more obvious in Newtonian physics.

Swinging a cannonball round and round has more angular momentum than swinging a Nerf ball. The only difference is mass, assuming the rope length and swing period are the same.