radar telescope question

[rnbs]

<span><p>Are signals received from a space probe by a DSN earth antenna, if it is not facing the probe at the time of reception? </p><p>That is, if the probe was an hour away, an antenna that spun into view of the direction in which the probe&rsquo;s radiation was coming from, a half hour after, an hour long radiated signal left the probe , and remained tracking to this direction as the earth turned, the earth antenna should pick up the radiation a half hour later and continue picking up radiation for another half hour. But does this happen?</p><p>If it does, is this because the radiated signal eg each modulated bit of the sequence making up the signal, is repeated for more than the assumed speed of light delay and therefore the speed of light delay is not necessarily proved or disproved by such communications?</p></span>

 

[MeteorWayne]

<p><BR/>Replying to:<BR/><DIV CLASS='Discussion_PostQuote'>Are signals received from a space probe by a DSN earth antenna, if it is not facing the probe at the time of reception? That is, if the probe was an hour away, an antenna that spun into view of the direction in which the probe&rsquo;s radiation was coming from, a half hour after, an hour long radiated signal left the probe , and remained tracking to this direction as the earth turned, the earth antenna should pick up the radiation a half hour later and continue picking up radiation for another half hour. But does this happen?If it does, is this because the radiated signal eg each modulated bit of the sequence making up the signal, is repeated for more than the assumed speed of light delay and therefore the speed of light delay is not necessarily proved or disproved by such communications? <br />Posted by rnbs</DIV><br /><br />Welcome to space.com!</p><p>Your question is worded kind of fuzzily. The time when the antenna must be pointing at the place where the satellite was at the time it was sent is determined by the light time. </p><p>For example, The Voyager 1 spacecraft is currently the furthest from the earth, about 109 AU away. If it sends a signal at midnight, it takes 15 hours and 9 minutes for that radio signal to reach earth. If you want to receive that signal, at 3 :09 PM in the afternoon, the antenna must be pointing at the place where Voyager 1 was at midnight. (It will be in a different place 15 hours later)</p><p>Point the antenna there at midnight, or even 3:08 or 3:10 PM and you will not receive the signal. You must point it there exactly when those emitted radio waves arrive.</p><p>Oh, and BTW, that should be a "Radio" telescope question. Radar is different, it uses a signal sent out reflected by the object, than the reflection is received. Voyager 1 would be too far away and too small for that to work (the return signal would be too faint.)</p><p>Wayne</p> <div class="Discussion_UserSignature"> <p><font color="#000080"><em><font color="#000000">But the Krell forgot one thing John. Monsters. Monsters from the Id.</font></em> </font></p><p><font color="#000080">I really, really, really, really miss the "first unread post" function</font><font color="#000080"> </font></p> </div>

 

[rnbs]

<span><p>The hypothesis that gravity is caused by charge polarization in atomic nuclei transverse to the tangential spin and orbital&nbsp; accelerations&nbsp;of the earth suggests that an airplane moving from west to east with the spin of the earth is very slightly more attracted to the earth than the same plane moving east to west - the greater the speed of the plane and closer to the equator, other things,winds etc, being adjusted for. Are the flyby gravitational anomalies consistent with this suggestion?</p><p>The attractive inverse fourth power force&nbsp;between a pair of&nbsp;colinear electrostatic dipoles becomes an inverse square force because&nbsp; each dipole acts to reduce the effect of the spin&nbsp;and orbital force on the other dipole, the nearer the dipoles are to each other. That is, the dipoles are made larger in proportion to the distance,r, between the dipoles. Thus the dipole dipole force is 9(10^9)(rqs)(rqs)/r^4.</p><p>The combined effect of all of the colinear dipoles along the earth's radii caused by the spin of the earth as well as along lines of longitude can produce the gravitational attraction of all objects and parts of the earth toward the center and a slight repulsion of parallel dipoles ie parts of the earth along parallel lines of longitude as perhaps&nbsp;in deep sea&nbsp;floor spreading and earthquakes.(see gravitymagnetismlight.org)</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p><p>&nbsp;</p></span>

 

[MeteorWayne]

<p><BR/>Replying to:<BR/><DIV CLASS='Discussion_PostQuote'>The hypothesis that gravity is caused by charge polarization in atomic nuclei transverse to the tangential spin and orbital&nbsp; accelerations&nbsp;of the earth suggests that an airplane moving from west to east with the spin of the earth is very slightly more attracted to the earth than the same plane moving east to west - the greater the speed of the plane and closer to the equator, other things,winds etc, being adjusted for. Are the flyby gravitational anomalies consistent with this suggestion?The attractive inverse fourth power force&nbsp;between a pair of&nbsp;colinear electrostatic dipoles becomes an inverse square force because&nbsp; each dipole acts to reduce the effect of the spin&nbsp;and orbital force on the other dipole, the nearer the dipoles are to each other. That is, the dipoles are made larger in proportion to the distance,r, between the dipoles. Thus the dipole dipole force is 9(10^9)(rqs)(rqs)/r^4.The combined effect of all of the colinear dipoles along the earth's radii caused by the spin of the earth as well as along lines of longitude can produce the gravitational attraction of all objects and parts of the earth toward the center and a slight repulsion of parallel dipoles ie parts of the earth along parallel lines of longitude as perhaps&nbsp;in deep sea&nbsp;floor spreading and earthquakes.(see gravitymagnetismlight.org)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <br />Posted by rnbs</DIV></p><p>Uhh, OK, I thought this was a serious question. Sorry...</p> <div class="Discussion_UserSignature"> <p><font color="#000080"><em><font color="#000000">But the Krell forgot one thing John. Monsters. Monsters from the Id.</font></em> </font></p><p><font color="#000080">I really, really, really, really miss the "first unread post" function</font><font color="#000080"> </font></p> </div>

 

[origin]

Replying to:<BR/><DIV CLASS='Discussion_PostQuote'>The hypothesis that gravity is caused by charge polarization in atomic nuclei transverse to the tangential spin and orbital&nbsp; accelerations&nbsp;of the earth suggests that an airplane moving from west to east with the spin of the earth is very slightly more attracted to the earth than the same plane moving east to west - the greater the speed of the plane and closer to the equator, other things,winds etc, being adjusted for. Are the flyby gravitational anomalies consistent with this suggestion?The attractive inverse fourth power force&nbsp;between a pair of&nbsp;colinear electrostatic dipoles becomes an inverse square force because&nbsp; each dipole acts to reduce the effect of the spin&nbsp;and orbital force on the other dipole, the nearer the dipoles are to each other. That is, the dipoles are made larger in proportion to the distance,r, between the dipoles. Thus the dipole dipole force is 9(10^9)(rqs)(rqs)/r^4.The combined effect of all of the colinear dipoles along the earth's radii caused by the spin of the earth as well as along lines of longitude can produce the gravitational attraction of all objects and parts of the earth toward the center and a slight repulsion of parallel dipoles ie parts of the earth along parallel lines of longitude as perhaps&nbsp;in deep sea&nbsp;floor spreading and earthquakes.(see gravitymagnetismlight.org)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <br />Posted by rnbs</DIV><br /><br />It appears that you hijacked your own thread to advertise your website.&nbsp; The entire contents of the above post will undoubtedly get you sent to the unexplained, because it does not make any sense - at least not to me! <div class="Discussion_UserSignature"> </div>

 

[MeteorWayne]

Replying to:<BR/><DIV CLASS='Discussion_PostQuote'>It appears that you hijacked your own thread to advertise your website.&nbsp; The entire contents of the above post will undoubtedly get you sent to the unexplained, because it does not make any sense - at least not to me! <br />Posted by origin</DIV><br /><br />Not only to you. It's a shame, it was an interesting question. I'll park it in the Unexplained while we discuss whether it is spam or not. <div class="Discussion_UserSignature"> <p><font color="#000080"><em><font color="#000000">But the Krell forgot one thing John. Monsters. Monsters from the Id.</font></em> </font></p><p><font color="#000080">I really, really, really, really miss the "first unread post" function</font><font color="#000080"> </font></p> </div>

 

[UFmbutler]

<p><BR/>Replying to:<BR/><DIV CLASS='Discussion_PostQuote'>The hypothesis that gravity is caused by charge polarization in atomic nuclei transverse to the tangential spin and orbital&nbsp; accelerations&nbsp;of the earth suggests that an airplane moving from west to east with the spin of the earth is very slightly more attracted to the earth than the same plane moving east to west - the greater the speed of the plane and closer to the equator, other things,winds etc, being adjusted for. Are the flyby gravitational anomalies consistent with this suggestion?The attractive inverse fourth power force&nbsp;between a pair of&nbsp;colinear electrostatic dipoles becomes an inverse square force because&nbsp; each dipole acts to reduce the effect of the spin&nbsp;and orbital force on the other dipole, the nearer the dipoles are to each other. That is, the dipoles are made larger in proportion to the distance,r, between the dipoles. Thus the dipole dipole force is 9(10^9)(rqs)(rqs)/r^4.The combined effect of all of the colinear dipoles along the earth's radii caused by the spin of the earth as well as along lines of longitude can produce the gravitational attraction of all objects and parts of the earth toward the center and a slight repulsion of parallel dipoles ie parts of the earth along parallel lines of longitude as perhaps&nbsp;in deep sea&nbsp;floor spreading and earthquakes.(see gravitymagnetismlight.org)&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <br /> Posted by rnbs</DIV></p><p><br /> <img src="http://sitelife.space.com/ver1.0/Content/images/store/5/3/c5b2cf5f-9433-40fb-836f-e95ee1e95076.Medium.gif" alt="" /><br />&nbsp;</p><p>This is what happens when someone finds a physics textbook, reads through it, understands NONE&nbsp; of it, but uses the terminology anyways. &nbsp;&nbsp;</p> <div class="Discussion_UserSignature"> </div>

 

[Mee_n_Mac]

<p>I think he's got it backwards.&nbsp; It's elbbub mug that causes people to stick to the Earth.</p><p>&nbsp;</p> <div class="Discussion_UserSignature"> <p>-----------------------------------------------------</p><p><font color="#ff0000">Ask not what your Forum Software can do do on you,</font></p><p><font color="#ff0000">Ask it to, please for the love of all that's Holy, <strong>STOP</strong> !</font></p> </div>