dangineer":324cn4ka said:
Doesn't a neutron decay into a proton and an electron (and a neutrino as well I believe)?
I think the problem with calculating the exact stability of large atoms lies in the fact that one would need to calculate the quantum states for a huge number of particles, which would be quite a feat.
actually antineutrinos..
And you are correct the exact calculation involved are those of QCD - Quantum Chromodynamic. With QCD we have 9 gluon ( actually 8 since one is actually a duplicate ) and the two methods of calculating the effects of strong force , lattice QCD Calculation and pretubative Method are very complex. Basically neither methods have been used on any nucleus more complex than Helium.
Before QCD, most nuclear Physicist use the shell method, (yes just like electron shells) or the liquid drop method.
also brings up a question I had in High School. Why does Helium have no isotope containing no neutrons? Why is Hydrogen the only element that occurs without them? Do Neutrons help bind the nucleus together until they hit a threshold where they start to weaken its integrity?
helium need a neutron due to the fact that while the strong force is stronger than electromagnetic force, the present of two particles of 1/2 quantum spin in the same quantum state, will interact via their quantum wave forms (or field, in this case Fermion Field), to generate a force called degenerative pressure. This pressure spread the particles apart, beyond the range of the strong force. So a dual proton or dual neutron system are unstable. The strong force itself doesnot not care if is a proton or neutron but Degenerative pressure does..Degenerative pressure is the reason behind Pauli Exclusion principle.
This also is what responible for configuration of electron obritals, and why only two electron are allow at ground state.