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#### mickeyl

##### Guest

So, "B" is riding in a rocket-ship that has a light-clock, that flashes 10-times per second, and is traveling at .8 the speed-of-light (240x10^9 meters-per-sec); and he passes "A" who is stationary and has a similar flashing-light-clock. After

the initial flash is synchronized, "A" sees his clock flash every .1-seconds (and "B" sees his light-clock flash every .1 second).

But, "B" after .1-second - travels 24x10^6; after 2-second travels 48x, after 3-seconds travels 72x, after 4-seconds travels 96x, after 5-seconds travels 120x10^6.

So: for each .1 sec. - after synchronizing flash = 0 ......... (for "B") .... (for "A")

flash1 = .1 plus 24,000,000/300,000,000 = .08 total ..... (.18sec) ..... (.1sec)

flash2 = .1 plus 48,000,000/300,000,000 = .16 total ..... (.26sec) ..... (.1sec)

flash3 = .1 plus 72,000,000/300,000,000 = .24 total ..... (.34sec) ..... (.1sec)

flash4 = .1 plus 96,000,000/300,000,000 = .32 total ..... (.42sec) ..... (.1sec)

flash5 = .1 plus 120,000,000/300,000,000 =.40 total ..... (.50sec) ..... (.1sec)

.................................................................................... __________________

....................................................................................... (1.52sec) __ (.5sec)

So, "A" sees his light-clock flash 5-times in .5-seconds; but he would see "B's" light-clock flash 5-times at a “slower” 1.52-seconds; (“slower” only because light-photons have to travel further to reach "A's" eyes) - therefore, "B's" clock has not slowed down. The further "B" travels, "A" continues to see "B's" clock flashing/ticking slowly. However, if "B" suddenly stopped "A" would see "B's" clock pulse again every .1-second. If "B" suddenly returned to earth at .8-speed of light (and if "A" could see "B's" light-clock), "A" would see "B's" light-clock pulse speed up, because the light-photons continually have less distance to travel to reach his eyes. But time always remains consistent and it has not slowed for either "A" or "B".