Okay, we have a new diagram here in post #14
Consider this. https://www.timeanddate.com/eclipse/umbra-shadow.html
, "How Large Is the Moon's Umbra? The size of the area on the Earth's surface covered by the Moon's umbra during a total solar eclipse depends, amongst other things, on the Moon's current distance from Earth. The smaller the distance, the larger the umbra. If the Moon is at its closest to Earth (its perigee) during the eclipse, the Moon appears larger in the sky. In that case, the umbra's path across the Earth's surface typically has a width of roughly 150 km (90 mi) at the Earth's equator. At higher latitudes, the Sun's rays hit the Earth's surface at a shallower angle, so the umbra's size grows accordingly. During some total solar eclipses, the umbra's path width reaches over 1000 km (600 mi) at the poles. If the eclipse occurs when the Moon's distance is greater, the tip of the Moon's cone-shaped umbra (see illustration) may only just reach the Earth's surface during parts of the eclipse, meaning that its diameter is close to zero..."
This means the umbra size during a total solar eclipse has a min and max size. Easy to convert into arcminutes here. Using 384401 km for mean lunar distance, then we have an umbra varying from about 1.3 arcminute in size on Earth to close to 9 arcminute size on Earth. The diagram showing umbra size 0.527 degrees is clearly wrong. The diagram shows an umbra > 31 arcminute size. In order for the umbra to be > 31 arcminute angular size on Earth, the Moon must also be very, very close to Earth too
In astronomy, we do not observe umbra angular sizes like this on Earth during total solar eclipses.