Thanks for the correction dangineer and ramparts. You are, of course, right that the four known fundamental forces are the strong nuclear, the weak nuclear, the electromagnetic, and gravity. As you pointed out, (visible) light is a small portion of the electromagnetic spectrum.
From what I've read there seems to be no upper boundary to the energy carried by photons (particles, waves, wave packets, or wavilcles - take your pick). The estimated temperatures immediately after the Big Bang seem to be telling me that. If there is, in fact, some theoretical limit to the amount of energy a photon can carry, based on the laws of physics as we know them, please let me know.
Conversely, is there a lower boundary for the amount of energy a photon can carry? The Cosmic Microwave Background is, as I understand it, equivalent to a temperature of about 2.7 degrees above absolute zero. What temperature would, say, a common AM radio wave represent? To an even greater extreme, what temperature would the electromagnetic radiation given off by an ordinary 60 Hz electrical transmission line represent? I think the wavelength would be ([~300,000 km/sec] x 1000 m/km)/(60/sec) = ~5,000,000 meters
I found the following information on page 5 of this website:
http://pvcdrom.pveducation.org/main.html
The graphic displayed on page 5 indicates that the wavelength of microwaves is on the order of 10^-2 meters and that the wavelength of radio waves is on the order of 10 meters. Since 10 meters is 1000 times larger than 1/100 meter does this mean that a black body emitting radio waves would be at a temperature of 0.0027 degrees above absolute zero? If this is so, wouldn't the Cosmic Microwave Background prevent such an object (if it was out in space somewhere) from getting below 2.7 degrees?
Chris