exoscientist":3ixrxrw9 said:
williammook":3ixrxrw9 said:
From surface to LEO 9.2 km/sec
From LEO to lunar trajectory is 3.85 km/sec.
From lunar trajectory to lunar touchdown 2.35 km/sec.
A total of 15.40 km/sec
A MEMs based rocket array produces 25,000 kg per sq meter and costs $2,500 per sq m to make out of silicon wafers. MEMS based rockets have a 1,000 to 1 thrust to weight ratio. So a sq meter masses 25 kg per sq m.
http://pdf.aiaa.org/preview/CDReadyMJPC ... 5_3650.pdf
MEMs rocket arrays provide a simple and reliable means to control the attitude of a rocket in flight. They also operate at very high efficiencies. This simplifies many of the systems in rockets. Meanwhile MEMs based gyroscopes and other sensor simplify avionics. Structural mass is therefore reduced to 9% total vehicle weight.
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Thanks for the response. For ease of accomplishing the mission, it might be better to purchase space on an existing launcher to get to lunar orbit.
Could you present your calculations just for a small lunar lander using MEMS propulsion?
Bob Clark
Bob, if you had a 20 kg (44 lb) 'eyeball' that I just described, that was 18 inches (457.2 mm) in diameter, you would have something that might be carried along on the next flight to orbit. The big issue is the orbital plane and timing. About 40% of space launches are geosynch orbits - and that means 8 to 10 flights per year. Equatorial orbit is not in the lunar plane. There are vector calculations to do for each launch window. The thing is, is to work with all the folks launching to geosynch and pick the best one to work with, and hitch a ride on there.
Best case, your geosynchronous transfer orbit, arcs out from the launch center toward the moon. In this case, you merely have to release after initial boost and apply additional corrective thrust. Best case you add only 0.85 km/sec, (1,900 mph) worst case you add something like 2.00 km/sec (4,472 mph)
This takes you to the vicinity of the moon. When you get close, you go in for a direct landing, and arrive at 2.4 km/sec (5,367 mph) which has to be reduced to 0 km/sec at 0 altitude. Slowing at 1/6th gee (1/3 gee thrust and 1/6 gee gravity) gives you a distance of D = v^2/ (2*a) --- a = 1/6 gee = 9.802/6 = 1.6337 m/s2 applying these figures obtains
D = (2400*2400)/(2*1.6337) = 1,762.91 km
Slowing at 1/3 gee - which requires an acceleration of 1/2 gee on the rocket reduces this to 881.45 km.
These figures are approximate since gravity forces change with distance, and speed changes with distance. A numerical solution, or a closed form solution using the potential equation would change them slightly. These would also be tensor based with a 3d vector field for the application of thrust - pointing in a specific direction in space at a specific point along the approach path. Again, simple application of physics gives you a ROM figure that's pretty close to reality.
Total delta vee of the vehicle after it separates from the rocket carrying it - ranges from 3.25 km/sec (7,267 mph) to 4.40 km/sec (9,839 mph)- depending on the rocket you hitch a ride on where it was launched from, and where the moon was when you separated and where you were and what direction you were going etc., etc., etc..
Since there are candidate rocket launches every other month or so, you have a rich field to choose from. A good PR campaign might hook you up for free!
As mentioned in one of my earlier posts I envision an 18 inch diameter ball - with a number of overlapping HDTV camera sets pointing in all directions at once. The surface of the sphere also has MEMs based phased array antennae that allows the sphere to operate as an 18 inch diameter directional antenna - pointing in any direction. Of course there are MEMs rocket arrays spaced around the sphere as well to provide orientation control as well as acceleration thrust.
Exhaust speed in the vacuum is 4.26 km/sec. Speed requirements for soft touchdown is 3.25 km/sec to 4.40 km/sec. This translates to a propellant fraction of
u = 1 - 1/exp(Vf/Ve) = 1 - 1/exp(3.25/4.26) = 0.5337
= 1 - 1/exp(4.40/4.26) = 0.6440
For a 20 kg (44 lb) device this is 10.674 kg of propellant (23.4828 lbs) at the lower speed. 12.880 kg (28.3360 lbs) to carry out this mission with MEMs rockets.
So the mass budget for the device is;
20 kg total mass
12.9 kg propellant mass
7.1 kg remainder
Now I mentioned earlier structural mass of 9% should be doable in this type of device. That's 1.8 kg - and includes all the camera chipsets and so forth - they're all MEMS! - carefully crafted and assembled. That leaves the balance 5.3 kg ADDITIONAL PROPELLANT!
Some of this will evaporate (and power the MEMs based fuel cells)
The rest will be used to move the little ball around the surface of the moon. This includes awesome camera shots - aerial flight as well as rolling along the surface. Resting the device lasts up to 20 days on what's left. Rolling on the surface it can move 6 hours or so - at hundreds of miles an hour. At slower speeds it will last longer. It can hover for 20 minutes.
So shots can be taken high, low and so forth.
I envision that the device will come in for a touch down at one of the 6 Apollo landing sites, do a quick circle taking only a few seconds around the entire site - this will allow the cameras to get enough data for a 3D data set if done right. Then coming to rest - perhaps atop the LM landing stage. Once the 3D model is built, a tour is planned, and the ball quickly zips through it.
The ball may have enough oomph to visit a second site. Let's find out
Here's the data on the 6 landing sites;
Mission... Site Location......... Latitude.... Longitude.... Date of Landing
11....... Mare Tranquillitatis.. 0°41'15" N 23°26' E..... July 20, 1969
12....... Oceanus Procellarum 3°11'51" S 23°23'8" W.. Nov. 19, 1969
14....... Fra Mauro............... 3°40'24" S 17°27'55" W Feb. 5, 1971
15....... Hadley-Apennines.... 26°06'03" N 03°39'10" E July 30, 1971
16....... Descartes................ 8°59'29" S 15°30'52" E April 21, 1972
17....... Taurus-Littrow.......... 20°9'55" N 30°45'57" E Dec. 11, 1972
We can use the dot product to figure out the distance and bearing between all of these points - there's quite a number of them. We take them two at a time p=a1,b1 where a and b is longitude and latitude. q=a2,b2
Any vector that points to a point on the surface of the moon will have length r=1,737.1 km. So the right side we have r^2 * Cos[angle between p & q] for the dot product. On the left side, we can pull the r's out of the dot product, and cancel them with the r's on the right side. Let t represent the angle between p and q. Then if the latitude and longitude of our two cities, p and q, are (a1,b1) and (a2,b2), we have
11 to 12 = 1,422.5 km initial bearing 264°58′43″
12 to 14 = 179.6 km initial bearing 094°46′37″
14 to 15 = 1,094.0 km initial bearing 033°17′29″
and so on...
Now, from this data, and knowledge of lunar gravity, we can calculate the speed needed to carry out a ballistic transport between these sites - and from that calculate how much propellant we need to burn.
A simplified estimate can be calculated using the formula for parabolic trajectory;
range = V^2 / g
assuming a 45 degree launch angle. Actual numbers will be slightly different but these will be close.
where V is the velocity we require, g is the moon's gravity 1.6337 m/s2 - we have the ranges calculated above, so we re-arrange the equation and solve for v
SQRT(range*g) = V
Transit.... Kilometers... Ballistic Velocity
11 to 12 1,422.50 km 1,524.45 m/sec
12 to 14 179.57 km 541.64 m/sec
14 to 15 1,093.96 km 1,336.86 m/sec
So taking the trajectory from Apollo 12 in Oceanus Procellarum to Apollo 14 in Fra Mauro takes 0.55 km/sec - and we calculate the propellant fraction needed to do that and we get;
u = 1-1/exp(0.55/4.26) = 0.12112
We calculated at landing that we had 5.3 kg of propellant aboard a 1.8 kg craft - for a total of 7.1 kg -to toss this total mass the distance needed requires that 12% of it be ejected by the rockets;
0.12112 * 7.1 kg = 0.8599587 kg ~ 860 grams ~ 0.9 kg (budget)
this we can easily do since we had 5.3 kg of propellant left when we arrived at the first landing site.
12 to 14 - 0.9 kg
14 to 15 - 1.7 kg
15 to 11 ... 962.2 km range initial bearing 139°59′36″
1,253.77 m/sec propellant fraction 0.254757885
4.5 kg propellant remaining - total mass at start 6.3 kg
1.6049728077 kg ~ 1.7 kg
2.8 kg of propellant is left over - divided among the four sites that 0.7 kg of propellant - that's enough to fly around the site a little ways, roll around the site a lot, and sit at the site for quite a while.
So, you can see after the vehicle lands at one site, it can fly to the others ballistically in a few minutes time - in less than a day the device can get high resolution 3D data sets of the sites, high resolution maps from above, and explore close up artifacts left behind and take some cool picture of the territory between the sites.
The vehicle masses 1.8 kg - and at $5,000 per kg - that's $9,000 to build one - once you do the engineering work needed to design it. That's about $6 million. I could get it done in 18 months - I'd like to build own and operate it. There's also the ground station which is another $4.5 million or so - this of course includes design of entire systems. The prize goes to the investors, I build own and operate the equipment and own the images produced.