I was wrong on this one. Sorry for the mistake!<br /><br /><font color="black"><font color="yellow">Again - what point are you trying to make? <br /><br />That your math is wrong, that you can do what if's on a spreadsheet?</font><br /><br />??????? that's not the point I'm trying to make. The point I tried to make is that that if you travel at the speed 1/sqrt(2) * c, assuming that for 100% of the trip is at that speed, then that will not be the quickest trip for the crew, but the Earth would go around the sun a minimum number of times by the time the crew returns.<br /><br /><font color="yellow">The point being made is that the original post is so wrong it is painful, and now he is trying to dig his way out and look like he meant to post something else...</font><br /><br />Look like? It's the same idea, just different numbers.<br /><br /><font color="yellow">In reply to:<br />--------------------------------------------------------------------------------<br /><br />"If you want to be home really soon, within the life time of your friends and family, you should travel at .707 c, and not any faster than that." <br /><br />If you travel too fast, your trip away from home will mean good bye forever to a generation of people on Earth. Travel slow enough and fast enough, departuring at the year 2070, and you'll be back from Alpha Centauri not so much later than the year 2087, if your stay at Centauri needn't be long.<br /><br />--------------------------------------------------------------------------------<br /><br />It don't get much wronger than that.</font><br /><br />Why? What do you mean?<br /><br />When I'm talking about the a "year" in terms of numbers, I'm talking about solar revolutions of the Earth.<br /><br />Crew Years will be extended, but the actual date at which they return to Earth would be earlier. The calendar on Earth is not influenced by space travel.<br /><br />I thought that if you travel closer and closer to the speed of light that time d</font>