Let me break this "thing" down.<br /><br /><font color="yellow">Well, like I said infinite density is not required, or so I think. <br /><br />BEFORE <br /><br />1). c = 186,000 miles per second</font><br /><br />Correct.<br /><br /><font color="yellow">AFTER <br /><br />1). c <sub>i</sub> = c > 186,000 miles per sec</font><br /><br />Under what conditions?<br />What does the letter i stand for?<br /><br /><font color="yellow">2). c <sub>v</sub> = c greater than or equal to 186,000 miles per second <br /><br />3). c = c <sub>v</sub> + c <sub>i</sub></font><br /><br />Why addition?<br /><br /><font color="yellow">c is 186,000 miles per second, so a .00001 second pulse is 1.86 miles long. For example, if I blasted a .00001 second laser pulse down a four-mile long straight tube, the entire 1.86 mile beam is moving at 186,000 miles-per-second, but it takes .00001 seconds for the entire length to get absorbed by my receiver at the end of the tunnel.</font><br /><br />Correct. I wouldn't call light a "length", since photons are not lines.<br /><br />What is the significance of the "four-miles" used here?<br /><br /><font color="yellow">c <sub>L</sub> = 1.86-miles in length <br /><br />For example, c <sub>L</sub> = c <sub>v</sub> + c <sub>i</sub>, so if c <sub>v</sub> = 186,000 miles per second, and c <sub>i</sub> = 0 miles per second then the total length of visible light is 1.86-miles.</font><br /><br />Correct.<br /><br /><font color="yellow">On the flip side, if c <sub>v</sub> = 186,000 miles per second, and c <sub>i</sub> = infinite miles per second</font><br /><br /> />> ???<br /><br /><font color="yellow">then we have a total length that is invisible</font><br /><br />invisible />> ???<br /><br /><font color="yellow">which may or may not be detectable, because of length contraction.</font><br /><br />Photons do not exceed the speed of light, but tachyons might (verification "pending").<br /><br /><font color="yellow">Now it would</font>