Does light-speed exist

[iron_sun_254]

C^2 can never equal C because when you square a value which includes units you need to square the units as well and that changes the value. You can't say "1 square mile equals 1 mile"

 

[siarad]

<blockquote><font class="small">In reply to:</font><hr /><p>"1 square mile equals 1 mile"<p><hr /></p></p></blockquote><br />Quite right but I'm talking of the speed of light, which can't be exceeded by information, which time & distance are, so C^2 can't be anything but C other than it's a number therefore dimensionless which I was told isn't true.

 

[aetherius]

How's this for us simpletons: <br />A = (4 miles)/(2 hours) = 2 mph.<br />A^2 = (16 miles)/(4 hours) = 4mph.<br /><br />If there is a constraint s.t. A <= 2 mph then that does not rule out using A^2 s.t. A^2 <= 4mph.<br /><br />I don't see a problem using C^2. I don't think the implication is that something is actually travelling at C^2. If a theory states that something travels at C^2 then that could be a problem unless you are talking about the speed of gravity.

 

[Saiph]

because your a^2 does not equal 4 mph.<br /><br />It equals 4 m^2 per hour^2. <div class="Discussion_UserSignature"> <p align="center"><font color="#c0c0c0"><br /></font></p><p align="center"><font color="#999999"><em><font size="1">--------</font></em></font><font color="#999999"><em><font size="1">--------</font></em></font><font color="#999999"><em><font size="1">----</font></em></font><font color="#666699">SaiphMOD@gmail.com </font><font color="#999999"><em><font size="1">-------------------</font></em></font></p><p><font color="#999999"><em><font size="1">"This is my Timey Wimey Detector.  Goes "bing" when there's stuff.  It also fries eggs at 30 paces, wether you want it to or not actually.  I've learned to stay away from hens: It's not pretty when they blow" -- </font></em></font><font size="1" color="#999999">The Tenth Doctor, "Blink"</font></p> </div>

 

[aetherius]

ummm...never mind. <img src="/images/icons/blush.gif" />

 

[patientzero]

When a ball is dropped it has to stop momentarily when it hits the floor before it can bounce back up. Does light also stop before it bounces off a mirror? Perhaps light speed can't be correctly calculated as a vector quantity since radiant energy has no explicit direction.

 

[Saiph]

actually, light does have a direction of propagation.<br /><br />As for requiring time to bounce after scattering...not sure actually. <div class="Discussion_UserSignature"> <p align="center"><font color="#c0c0c0"><br /></font></p><p align="center"><font color="#999999"><em><font size="1">--------</font></em></font><font color="#999999"><em><font size="1">--------</font></em></font><font color="#999999"><em><font size="1">----</font></em></font><font color="#666699">SaiphMOD@gmail.com </font><font color="#999999"><em><font size="1">-------------------</font></em></font></p><p><font color="#999999"><em><font size="1">"This is my Timey Wimey Detector.  Goes "bing" when there's stuff.  It also fries eggs at 30 paces, wether you want it to or not actually.  I've learned to stay away from hens: It's not pretty when they blow" -- </font></em></font><font size="1" color="#999999">The Tenth Doctor, "Blink"</font></p> </div>

 

[MBA_UIU]

When a ball is dropped it has to stop momentarily when it hits the floor before it can bounce back up. Does light also stop before it bounces off a mirror? The answer is in the how the energy is transferred. When light hits an object the object acts has a capacitor collecting part of that light and reflecting it back as the color in which we see. The ball on the other hand is its own the capacitor storing its energy in its elastic material. <div class="Discussion_UserSignature"> <p><strong><font color="#0000ff"><br /><br /> <br /><img id="268587ce-7170-4b41-a87b-8cd443f9351a" src="http://sitelife.space.com/ver1.0/Content/images/store/6/8/268587ce-7170-4b41-a87b-8cd443f9351a.Large.jpg" alt="blog post photo" /><br /></font></strong></p> </div>