Explanation for cosmological red shift of light

[Classical Motion]

Radio photons.

 

[marcin]

Are radio photons emitted by the AC powered antenna also binary?

 

[Classical Motion]

Yes.

 

[marcin]

Why?

 

[Classical Motion]

Because a photon is emitted as a chunk of field, but you can't see it unless you feed the antenna with a rectified signal. A precision rectified signal with a waveform generator. And if you set the generator to a one shot function, and just feed 180 degrees into antenna..... you will get one radio photon emitted.

 

[marcin]

Why do you think, that this emitted chunk of field doesn't have a continuous EM oscillation in its partial wavelength range?

 

[Classical Motion]

What does that mean, please re-state.

 

[marcin]

AC is the oscillating current, which produces the oscillating EM field. What is binary in this continuos oscillation?

 

[Classical Motion]

Yes it does produce an alternating field. But what I am trying to tell you is that you don't need an oscillating field to emit a radio wave.

One field is all that's needed, for a ground antenna.

A dipole requires bi-polar fields, but the fields do not have to alternate.

You can see this for yourself. That is my only reference.

From your questions, I'm sure you do not understand the implications of a chunk of field. I can try to explain it to you, if you want. So you might understand this dynamic.

 

[marcin]

Don't bother. What I'm trying to tell you is that there are also oscillating currents that produce the oscillating fields, but you claim, that they are binary too. Why are these oscillating fields binary?

 

[Classical Motion]

Ok, you don't get it. I worked with radio all my life, and I thought I knew what I was doing. Then I found out I did not know what I was doing, and no one else did too.

An antenna is a transducer. It converts an angular EM field into an linear EM propagation. Upon RX, is converts a linear EM wave back into an angular EM field.

Only going into and out of antenna comes angular field(oscillatory) Waves.

The path between the antennas is linear, a chunk, a duration, of field. That chunk is emitted in an instant. Because the field is already at c speed, and emission is just a change in direction.

With an AC signal in, the chunk is emitted every 180 degrees. Two chunks emitted for every full oscillation in. With a waveform generator, we can insert this 180 and only that 180 in.....to show and see this. One at a time.

This probably is confusing even if you were familiar with radio.

That's why I have an experiment. Seeing is believing.

 

[marcin]

https://en.wikipedia.org/wiki/Radio_wave

Is this correct?

Are you going to deny the EM field oscillation?

 

[Classical Motion]

That's a sound wave, not an EM radiation. EM Radiation is chunky.

 

[Classical Motion]

Those examples is what we all have been taught.

 

[marcin]

With an AC signal in, the chunk is emitted every 180 degrees. Two chunks emitted for every full oscillation in. With a waveform generator, we can insert this 180 and only that 180 in.....to show and see this. One at a time.

The first animation shows your chunks. There is a continuous EM oscillation within a single chunk. It's in the *half wavelength range. I referred to it in this comment.

I may even agree with you that the emission of a single chunk is binary - it's emitted or not, but there is nothing binary within in.

 

[Classical Motion]

Those aren't chunks, those are streaming Doppler waves. EM radiation has a duty cycle, not an alternating frequency. My experiment shows this.

Think of a wheel hub and spokes but no rim, just spokes. Spin hub. Release spokes. All the spokes are emitted in an instant and all spokes are already at velocity, when emitted, all they did was change direction.

Immediately after emitted, new spokes start to grow. They grow to a length of 1/2 wavelength, which is 180 degrees, then emitted. New spokes grow every 180 degrees and are emitted.

That gives a spoke duration of 1/2 period, 1/2 wavelength fly by..... AND a 1/2 period, 1/2 wavelength of space fly by(duration)...... in between every chunk. Between spokes.

That's with no relative displacement. If there is displacement.... ONLY the space duration changes with distance change..... NOT the spoke length. Spoke length stays constant.

The redshift shift is a duty cycle shift. But only the space of the duty cycle change, not photon length.

 

[marcin]

There is no such thing as a Doppler wave. There is a Doppler effect on different sorts of waves, particularly EM waves.

 

[Classical Motion]

I’ve always wondered why so many seem to understand expanding shells, but can’t understand a photon shell.

Some of mine are about 100 LY in diameter now.

 

[marcin]

That's why I have an experiment. Seeing is believing.

Record a video and show me your duty cycle shift.

 

[Classical Motion]

I'm too old and decrepit. Try it and see for yourself.

 

[marcin]

I actually don't care, but you should care if you try to convince anyone.

 

[Classical Motion]

Ok. Didn't mean to disturb you.

 

[Atlan0001]

Ok. Didn't mean to disturb you.

Don't give way, CM! You're neither that old nor that decrepit! He's attacking you personally trying to diminish you. You were holding on pretty well to your limits. I, for one, enjoy reading you whether I understand you well or agree with you or not. That is the way to inspiration sometimes. Stay your course on the forum no matter marcin.

I wasn't following you two specifically but generally . . . maybe:

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Inverse-square law - Wikipedia

en.wikipedia.org

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[marcin]

No @Atlan0001 I was attacking the idea of a binary photon and you are defending it and taking it personally because the core idea (binary base) is your child.

 

[Atlan0001]

No @Atlan0001 I was attacking the idea of a binary photon and you are defending it and taking it personally because the core idea (binary base) is your child.

You betcha, inclusive of Trojan!