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brooklynspacecadet
Guest
first let me thank you for the excellent illistration and explanation.<br />yes, you have explained things but it creates more questions. first of all you mention that "If you divide 230 to get the radius then square that number and multiply it by Pi you get 41,548 square feet as the area of the dish" why do you square it and multiply it by pi? what is the reason for that specific multiplication? please explain your mathematical objective and why you initiated it.<br />I also don't understand by have 41,548 as the square footage of the dish allowing each square foot to be the equivalent of reaching one mile or one square mile. how does the feet and miles go together? and then you go on to stretch the distance by the 36 million miles by square feet of the dish. <br />I also dont understand what you mean when you say "the dish focuses all of that area onto a smaller antenna that is one square foot in area. Now you have a ratio of 41,548 to 1 " if the dish that is being focused on is big or small why would it make it a ratio of 41548 to 1?<br />additionally you illustrate using a parabolic example to amplify receiving sound and signal. but how about sending signals? you said the antennae is actually very weak on the space rovers and of course the topic is it's so many millions of miles away. so how does the rover receive signals and commands without having the satellites huge disk and only having a small antennae?<br />untill i figure out how the math defines the physics or maybe it should be vice versa this will still seem like amazing magic and skepticism to me.