Replying to:<BR/><DIV CLASS='Discussion_PostQuote'>The question is as follows -- The distance from Earth of the Red Supergiant Betelgeus is approximately 427 LY. If it were to explode as a supernova it would be one of the brightest stars in the sky. Right now the brightest star other than the Sun is Sirius, with a Luminosity of 26Lsun and a distance of 8.6 LY. How much Brighter than sirius would the Betelgeus supernova be in our sky if it reached a maximum luminosity of 10 ^10 Lsun? I know we need to use the calculation of Apparent Brightness = Luminosity / 4 pie R squared and find a ratio, but I am stuck at what the problem would look like. Any help would be greatly appreciated Thankyou <br />Posted by <strong>ASTRONOMYCLASS</strong></DIV><br /><br />Let me point the way with 3 questions. How much brighter would Sirius appear to be to us here on Earth if, keeping it's distance @ 8.6 LY, it went from 26 to 10^10 Lsuns ? (I'm assuming Lsun is luminosity relative to the Sun, ie 26 times or 10^10 times as luminous as the Sun) If 2 things have the same luminosity but differ only in their distance from the Earth, what's their difference in apparent brightness (using your formula). If it helps lets say you have a star with 1Lsun at 8.6 LY and another star with 1Lsun @ 427 LY. What's the apparent brightness of each ? <div class="Discussion_UserSignature"> <p>-----------------------------------------------------</p><p><font color="#ff0000">Ask not what your Forum Software can do do on you,</font></p><p><font color="#ff0000">Ask it to, please for the love of all that's Holy, <strong>STOP</strong> !</font></p> </div>