Explanation for cosmological red shift of light

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Atlan0001

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1.) When the light (t=0) is 4 x 9-trillion kilometers away from (t=0) REALTIME NOW source of emergence, the SPACETIME (t=+1) past histories' asymptotic curve away from the line of reality is 4 years; 4 light years, and a certain amount of gain in red shift for 4 light years. A SPACETIME (t=-1) future histories' light is in process of spontaneous emergence from the (t=0) REALTIME NOW of sources.

2.) When the light (t=0) is 2.3 million x 9-trillion kilometers away from (t=0) REALTIME NOW source of emergence, the SPACETIME (t=+1) past histories' asymptotic curve away from the line of reality is 2.3 million years; 2.3 million light years, and a huge amount of gain in magnitudinous periphery and, thus, red shift for 2.3 million light light years over 4 light years. A SPACETIME (t=-1) future histories' light is in process of spontaneous emergence from the (t=0) REALTIME NOW of sources.

3.) When the light (t=0) is 5 billion x 9-trillion kilometers away from (t=0) REALTIME NOW source of emergence, the SPACETIME (t=+1) past histories' asymptotic curve away from the line of real-time reality is 5 billion years; 5 billion light years, and a vastly greater amount of gain in magnitudinous periphery and, thus, red shift for 5 billion light light years over 2.3 million light years. A SPACETIME (t=-1) future histories' light is (possibly) in process of spontaneous emergence from the (t=0) REALTIME NOW of sources.

4.) When the light (t=0) is 10 billion x 9-trillion kilometers away from (t=0) REALTIME NOW source of emergence, the SPACETIME (t=+1) past histories' asymptotic curve away from the line of real-time reality is 10 billion years; 10 billion light years, and a vastly, vastly, greater amount of gain in magnitudinous periphery and, thus, red shift for 10 billion light light years over 5 billion light years. A SPACETIME (t=-1) future histories' light is (possibly) in process of spontaneous emergence from the (t=0) REALTIME NOW of sources.

5.)....

An accelerating expansion of distance, periphery, bounces, magnitudes (summed up in red shift)...?!
 
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Atlan0001

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Ad#102:

"An accelerating expansion of distance, periphery, bounces, magnitudes (summed up in red shift)...?!"

Depths and densities of accumulating content over space and time . . . red shifting . . . from a 2-d 'Mandelbrot set' in every point of a photo-frame horizon of streaming SPACETIME?!
 

marcin

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#102
1-5.) When the light (t=0) is X billion x 9-trillion kilometers away from (t=0) REALTIME NOW source of emergence, the SPACETIME (t=+1) past histories' asymptotic curve away from the line of real-time reality is X billion years; X billion light years, and a vastly, vastly, greater amount of gain in magnitudinous periphery and, thus, red shift for X billion light light years over Y billion light years. A SPACETIME (t=-1) future histories' light is (possibly) in process of spontaneous emergence from the (t=0) REALTIME NOW of sources.
X > Y. There is no more information in it. Thank you for writing it only 4 times.
 
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Atlan0001

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#102

X > Y. There is no more information in it. Thank you for writing it only 4 times.
You're welcome. I could have written it as many times as it exists but that would have taken an infinite amount of space and time and I'm not quite that interested. Besides which you didn't do a bad finishing job I was too tired and too preoccupied at the time to think of. As a teacher throughout my careers and many decades, I like it and don't mind at all when a student gets ahead of me as a few here have done over a goodly number of times, showing me up, and beats me to a finish line. It's what teachers should always work for and hope for.
 
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marcin

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@Atlan0001
((+1) (-1)) = 1/0
((+1) (-1)) = 1 and/or 0 (fundamental binary base2, plus Trojan).
Is there a mathematical operation in your equation? Is there implicit operator between (+1) and (-1)?
Where is this Trojan in your equation? What is it?
 

Atlan0001

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@Atlan0001

Is there a mathematical operation in your equation? Is there implicit operator between (+1) and (-1)?
Where is this Trojan in your equation? What is it?
Division (Chaos) (binary base2 (2)) (an equal but opposite) (0) (infinity) (superposition) ("Spooky action at a distance") (the unobserved and unobservable) (....) will have its full half-portion ((+1) (-1)) if it has to take it, rip it, the anti, the negative and/or the positive, whichever, out of the G.U.T. of Unity (1)! Enter then, also, the third dimension to the base of 2, the Trojan!

One of these days, maybe, you might gain the third eye called 'perception'. There is always hope.

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"Great spirits have always encountered violent opposition from mediocre minds...." -- Albert Einstein.
 
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Atlan0001

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@Atlan0001 Is there implicit operator between (+1) and (-1) in your equation ((+1) (-1)) = 1/0 ?
One output of atom smashing is division into matter / anti-matter. What is the operator?

(((+1) (-1)) = 1 (Unity) / 0 (Chaos)).

(SPACETIME coordinate points past histories (t=+1 (-->>)) -- SPACETIME coordinate points future histories (t=-1 (<<--)) = t=1 (collapsed cosmological constant (/\) Horizon) / (t=0) REALTIME NOW (t=0) (Hawking's clock and time on the clock. of his "Grand Central Station of the Universe." The place and time where Einstein ended up in his mind's eye trip to the speed of light.

===============
===============
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(<<--)
(-->>)
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And too much more cosmology, et-all, to introduce here....
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"Great spirits have always encountered violent opposition from mediocre minds...." -- Albert Einstein.
 
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marcin

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Jul 18, 2024
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One output of atom smashing is division into matter / anti-matter. What is the operator?
If you show me the equation of this transition, I'll tell you where the operator is.
(((+1) (-1)) - 1 (Unity) / 0 (Chaos)).
You replaced equals sign with a dash (I'm just guessing that it's not a minus sign), so it's no longer equation. Your previous answer with your latest change tell me, that there is no implicit operator between (+1) and (-1). There is only the assignment of (+1) to 1 (Unity) and the assignment of (-1) to 0 (Chaos).

*You changed it back to equals sign, so it's equation again. If it's equation, there should be an operator between (+1) and (-1). What is it?
 
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marcin

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Why do you use mathematical symbols to draw your symbolic picture, if these symbols already have a meaning that is inconsistent with your representative illustration?
 

marcin

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And you're a genius with your 142 IQ, your understanding of complexity, chaos theory and all the cosmology. My bad.
 

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