# StargazingDetermintion of milky way's SMBH mass from surrounding plasma disc's motion at event horizon.

#### bibhutibhusanpatel@gmail.

Star Dynamic Gravitational Constant G*(approximately equal to Universal Gravitational Constant G) has successful application in astronomy for determination of milky way's supermassive black hole mass from measurement of rotating plasma disc's motion at event horizon with periodic flare.

#### bibhutibhusanpatel@gmail.

Star Dynamic Gravity G* = Dynamic Force of stars in motion = Dynamic Force of Supermassive Black Hole at center of the galaxy.

Dynamic Force = effective mass(actual mass ×distance between event horizon and center of the SMBH)× velocity/unit time(= velocity of disc/Time period of flare in rotation).

#### bibhutibhusanpatel@gmail.

Dynamic Fòrce = Mass of SMBH × Distance parameter expressed by simple number of units without dimensions × velocity of plasma disc at event horizon/Time Period of flare's rotation = Star Dynamic Gravity Constant G*.

#### bibhutibhusanpatel@gmail.

To obtain result compared to earth rotation,a multiplication with a factor of 2Pi (=2×3.1415) is done with velocity. Thus,calculation for this observation can be worked out.

#### bibhutibhusanpatel@gmail.

So,when flare has a time period half of unity value (or equal to 12 hours) the velocity is one complete orbit in that time,thus rotates twice in a day.This result is calculated in comparison with the earth's rotation around the axis.

#### bibhutibhusanpatel@gmail.

Note : Dynamic Force = Mass × Star Dynamic Gravitational Constant G*.So,when mass is unity numerical value of G* is equal to Dynamic Force,is a special case.

In comparison to dynamics of earth,the result for calculation of mass of supermassive black hole at the center of milky way is found to be =( Pi)3.1415 × 1.3 × 10 to the power 6 × 1.04 = 4.2 × 10 to the power 6 solar mass.

Here,three sets of balanced dynamics are obtained.
First.The dynamics of Sgr. A,supermassive black hole at the center of milky with mass to be calculated at a distance of 0.1 A.U. from the swirling gas plasma with a time period of rotation 1 or 2 and having velocity v/2 or v respectively.

Second.The dynamics of sun at a distance of 27,000 light years from the center of galaxy milky way with a time period of orbit 26,000 years.The ratio of these two terms is 27,000 ÷ 26,000 = 1.04.

Third.The dynamics of earth with a mass ratio of 1.3 × 10 to the power 6 : 1 to the sun;disttance between them is 1 Astronomical Unit and is rotating around own axis once in a day.

The unit velocity is for a unit radial distance of motion obtained by multipliction of term velocity(v)/time period of flare by 2 × Pi(=3.1415).

#### Classical Motion

One needs to be wary of rotation, for it will mislead you. A mathematical rotation is much different than a physical rotation.

A rotation contains two concepts. The first is a 360 degree swing(this is constant)........along with a 360 degree length, the circumference. A mathematical rotation always has a straight swing.......giving a circumference of 3.14 times the diameter. pi.

But nature NEVER makes a straight swing. And pi is not valid. In a natural rotation, pi, is always larger than 3.14. There is no set ratio of diameter(or radius) to the circumference in a natural rotation. This concept of rotation is variable.....with nature. This non straight rotation also takes more time than expected.....with pi. pi will mislead you with nature.

Therefore the the calculation of velocity(both speed and direction) and momentum.... of stars, planets and particles are invalid.

An orbit is a small rotation pulled and stretched into a larger rotation. A one turn helix formed into a circle.

A rotation within a rotation.