S
Saiph
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mlorrey: actually it doesn't use E=mc^2. it uses the full version of the equatin, <br /><br />e^2=m^2*c^4+p^2*c^2<br /><br />Photons have no rest mass, so m=0. They do have energy, and so they must then have momentum.<br /><br />So, it doesn't use the m*c^2 part of the equation, so the statement that it's based on e=mc^2 is technically wrong, and will give you the wrong answer. <div class="Discussion_UserSignature"> <p align="center"><font color="#c0c0c0"><br /></font></p><p align="center"><font color="#999999"><em><font size="1">--------</font></em></font><font color="#999999"><em><font size="1">--------</font></em></font><font color="#999999"><em><font size="1">----</font></em></font><font color="#666699">SaiphMOD@gmail.com </font><font color="#999999"><em><font size="1">-------------------</font></em></font></p><p><font color="#999999"><em><font size="1">"This is my Timey Wimey Detector. Goes "bing" when there's stuff. It also fries eggs at 30 paces, wether you want it to or not actually. I've learned to stay away from hens: It's not pretty when they blow" -- </font></em></font><font size="1" color="#999999">The Tenth Doctor, "Blink"</font></p> </div>