C
chebby
Guest
Hi,
I was thinking if we ever will get to travel at speeds close to speed of light, what would be the most efficent speed (from the point of view of earth as they want you to return as soon as possible)?
For example let's say we are traveling to a star close 4 light years away. To make it easy let's discard acceleration (it makes calculations harder) and use a scenario when you leave and arrive with the same speed (I know it's unrealistic but to keep things simple). To do this I made a table listed below that used Relativistic Factor I got from the relativistic calculator from http://www.1728.com/reltivty.htm
From the point of view of people in the spaceship it is easy - the closer speed is to 1.0 the better. Therefore going at .999 is the best, it gets people to the star in 4.04 years. However, a whooping 90.4 years passes on earth. Not good.
Let's try a speed of .1, then 40.4 years will pass on earth, also no good.
By trying different values I found .78 to give the smallest time (8.2) years.
I think a differential equaltion can be set up to find the most efficient speed, but I it's been a while since my calculus classes so I would prabobly need some help. ALso, maybe somebody already figured out the formula for this and I am just not aware?
The second part of my question is about fuel efficiency (I know it grows by the same factor.) Would going at the most time efficient speed also be the most efficient speed for fuel expenditure?
thanks,
Chebby
I was thinking if we ever will get to travel at speeds close to speed of light, what would be the most efficent speed (from the point of view of earth as they want you to return as soon as possible)?
For example let's say we are traveling to a star close 4 light years away. To make it easy let's discard acceleration (it makes calculations harder) and use a scenario when you leave and arrive with the same speed (I know it's unrealistic but to keep things simple). To do this I made a table listed below that used Relativistic Factor I got from the relativistic calculator from http://www.1728.com/reltivty.htm
From the point of view of people in the spaceship it is easy - the closer speed is to 1.0 the better. Therefore going at .999 is the best, it gets people to the star in 4.04 years. However, a whooping 90.4 years passes on earth. Not good.
Let's try a speed of .1, then 40.4 years will pass on earth, also no good.
By trying different values I found .78 to give the smallest time (8.2) years.
I think a differential equaltion can be set up to find the most efficient speed, but I it's been a while since my calculus classes so I would prabobly need some help. ALso, maybe somebody already figured out the formula for this and I am just not aware?
Code:
<pre>
********************************************************************************************************************************************
distance (light years) speed(in C) Rfactor SpaceshipTime(T(years)=d/speed) Earth TIme(T(years)=Tspaceship * RF)
4 .1 1.01 40.0 40.4
4 .5 1.15 8.00 9.2
4 .78 1.60 5.13 8.2
4 .8 1.67 5.00 8.35
4 .95 3.20 4.21 13.472
4 .999 22.4 4.04 90.495
********************************************************************************************************************************************
</pre>
The second part of my question is about fuel efficiency (I know it grows by the same factor.) Would going at the most time efficient speed also be the most efficient speed for fuel expenditure?
thanks,
Chebby