Hello Neil.
I am trying to quickly summarize the answers and some more details, sorry that it has become so extended but I wanted to be clear.
Your quote
~true but the the portion just above the water level needs to support nearly all the weight above about 10 kilometers~
At any particular operational elevation; a buoyant object; (balloon, must account for their structural mass and still provide upthrust for a payload some inefficient balloons use a ratio of 1/5 e.g. if the gross upthrust is 125 kg, 25 kg are part of the shell and gondola, which leaves a net 100 kg remaining that is used for payload and maneuvers
Your quote
~in very deep water, each mooring line can be attached to ship which allows the base to be moved to recover balance if the lean becomes excessive due to winds, human error or partial failure of the whole assembly. Locating at the Brad Edwards sweet spot in the South Pacific would greatly reduce the wind, storm and lightning problems~
I will respond to this after clarifying your misunderstanding about multiple CG. Indeed, CG stands for center of gravity. You stated:
Your quote
~How can there be a multiple center?~
I never said, or implied, multiple CG! What I said was that there are multiple centers of buoyancy. These are not the same thing. At this time I will not go into profound descriptions but a center of buoyancy lays below a waterline and in the case of a SpaceShaft the CG is above the waterline.
The reason why there are multiple centers of buoyancy is because every time mooring lines are placed to stabilize the structure far below a waterline, (i.e. a reference line that indicates the fluctuant elevation of an object relative to a plane,) a new center of buoyancy is generated between the moored elevation and the waterline.
Mooring lines, which are a completely separate system from the anchoring, do take care of wind, Coriolis, and Center of Buoyancy, i.e. horizontal displacements. While anchoring, together with ballasting, takes care of vertical displacements.
Your quote
~You must be thinking square kilometers near the base (large taper) to get to 100 kilometers with a material weaker than diamond~
Regarding your assumption of REALLY extended areas; it will be great if such will be permitted! However, the ones I where proposing were only with an external diameter of about 300 m at the out-most shaft and 50 to 100 m on the internal.
I believe you are miscalculating the cumulated buoyancy. Loss of efficiency with altitude is due to air density and this can be graphically illustrated as an upside-down half-parabola. The precise calculations can be done using the barometric formula. For simplicity, throughout the regions where buoyancy is possible, you must not consider the structural mass as weight, but consider weight in relation to a waterline.
I will give you an example but I will not write all the calculations because I do not consider this forum a place to write science but to express opinions, i.e. it is very cumbersome and inefficient to work with and it will inevitably lead to errors and misunderstandings. For the science stuff you will need to attend the conferences or request the papers which are elsewhere available.
Say you manufacture a super-pressurized science balloon capable of transporting 30 kg like
http://www.ssc.se/?id=7697. We know that when fully inflated this zero pressure balloon has a diameter of +/- 14.5 m. If instead of being a zero pressure balloon it was a super-pressurized balloon of the same diameter; the upthrust capability of such a balloon at sea level will be almost 1.3 tonnes. Between sea level and up to the proposed operational altitude of the zodiac balloon; you could fit into a imaginary column a number of 1725 of such balloons. Evidently the upthrust will decrease with altitude as a function of the decrease of air density, but the net upthrust capacity is the sum of all the balloons. That is, at an elevation of +/- 30 m having 2 balloons stacked you will have 2.6 tonnes, 3.9 t at 45 m, ... and like this you add up all the values, taking into account the loss of buoyancy with height as you can calculate using excel and the barometric formula. And it is a fact that the intent is not to cram each balloon with cargo/payload and so cancel the buoyancy of every balloon, but to obtain a specific force at the top of the SpaceShaft being superior to the weight generated by the inflatables above the buoyancy line, or chosen waterline. A task very much like jacking up a car.
Evidently reaching a certain altitude is not the same as orbital insertion. And I never claimed that a SpaceShaft can do such a thing, but neither can do it the CNT tether. Both systems are only capable of assisting in the launch of spacecraft. The CNT tether gives the impression that it will release spacecrafts at GEO altitude. What this means is that a spacecraft at this altitude will still need to navigate away from the GEO station. Besides the high traffic of junk being incremented, there is still the needed independent maneuvers by the spacecraft to home towards other orbital regions. And any cargo meant to be brought back to Earth will require the spacecraft to go back to those predefined stations. In the case of a SpaceShaft, the launching and landing can happen at altitude regions where there is less traffic and with little amount of needed energy for orbital insertions by the spacecraft. And this without taking into account the safety fact that a SpaceShaft cannot fall back to the planet surface because is a buoyant structure.
Consider the following: The shuttle/ISS only goes up to a max of about 400 km. In fact any other rocket, (and also so the shuttle,) uses its first stage just to travel to an altitude of 100 km, perpendicular to Earth's surface. After consuming all the fuel and the release of the tanks and engines, (of the first stage,) it is inertia that takes over and keeps aloft the remaining mass, (payload, second stage, etc.). Until the next propulsion blast from the 2nd stage happens. As said all this happens at just an altitude of about the Karman line, you can call this the freefall intermezzo, during which the max upward velocity is a meager 100 to 300 km/hr, (depending on the model and maker,) and for a few seconds, the rocket is moving upwards only due to diminishing inertia. But it is during this time that it has to maneuver to get the inclination needed as to fire the next engine, i.e. 2nd stage, which is intended to produce the tangential velocity for orbital insertion.
Very much as this 1st stage upthrust is what brings the rocket into position for orbital insertion, so can a SpaceShaft elevate a small/medium size rocket into space and so providing very unexpensively the altitude for an assisted launch. Include to the list of applications; touristic gliders (like Virgin's SpaceShipTwo), microsatelites (and satellites), or even landings from orbital spacecrafts. One thing the regular CNT tether cannot offer are high atmospheric facilities which would house human researchers. Other noticeable properties is that the system is transportable something the CNT tether is not.
With what I wrote here I may not have been as clear as I would have liked to be, but I hope it has been clear enough. I will insist you study the designs I've made and are found at the website (
http://spaceshaft.org). There is one drawing in which cube-like balloons are attached to each other forming a sectional-ring of 36 units. Such ring is should be about 50 m in diameter totaling 3.6 tones of upthrust per ring at sea level. These rings are then stacked and are secured with inflatable beams, which are also buoyant and are intended to help in the structural toughness. These beams are somewhat like TensAirity beams, (see the reference section,) which provide a high resistance to bending/deflection.
References
Sphere volume:
http://en.wikipedia.org/wiki/Sphere#Volume_of_a_sphere.
Mass of air at sea level:
http://en.wikipedia.org/wiki/Atmosphere_of_Earth.
Barometric formula:
http://en.wikipedia.org/wiki/Barometric_formula.
Center of Buoyancy:
http://en.wikipedia.org/wiki/Center_of_buoyancy.
TensAirity:
http://www.google.com/search?um=1&hl=en ... a=N&tab=iw
best regards