Disproving special relativity
In Newtonian mechanics, we have Galilean Transformation between two inertial reference frames:
X' = X - vT
Y' = Y
Z' = Z
T' = T
where v is the speed of the origin of the inertial reference frame represented by Galilean spacetime (X', Y', Z', T') relative to the origin of the inertial reference frame represented by Galilean spacetime (X, Y, Z, T).
We can prove that clock time is the same as Galilean time T:
Since clock time Tc is defined by the number of cycles N of a physical periodical process:
Tc = N/k
where k is a calibration constant and equals 9,192,631,770 for a cesium atomic clock.
The clock times Tc and Tc' of two clocks attached to the inertial reference frames defined by Galilean spacetime (X, Y, Z, T) and (X', Y', Z', T') above are
Tc' = N'/k
Tc = N/k
where
N' = T'/P'
N = T/P
P' is the period of the clock on (X', Y', Z', T') and P is the period of the clock on (X, Y, Z, T).
As in Newtonian mechanics, time is absolute, we have P' = P and thus
Tc' = N'/k = (T'/P')/k = (T/P)/k = N/k = Tc
which means the time shown on the moving clock is always the same as the time shown on the stationary clock, i.e., the clock time is absolute and independent of the reference frame. If we choose k = 1/P, then
Tc' = Tc = N/k = (T/P)/k = T (1/P)/(1/P) = T
That is, in Newtonian mechanics, clock time is the same as the absolute Galilean time.
But Einstein uses Lorentz Transformation to introduce a new set of space and time (called relativistic space and relativistic time) which is mathematically equivalent to the redefinition of space and time:
x' = γX'
y' = Y'
z' = Z'
t' = (1/γ)T' - (γv/c^2)X'
where γ = 1/sqrt(1 - v^2/c^2), (x', y', z', t') is the relativistic spacetime coordinate system with the same origin and same directions of space axis's of the Galilean spacetime (X', Y', Z', T'), and v is the speed of the origin relative to the medium of light, aether. When v = 0, relativistic spacetime (x, y, z, t) becomes the same as Galilean spacetime (X, Y, Z, T):
x = X
y = Y
z = Z
t = T
Yes, Einstein has the right to introduce new spacetime, but he must also change the design of clocks to adapt to his new relativistic time. In reality, the principle of physical clocks have not been changed according to relativity and thus clocks still measure the absolute time. The change of the definition simply means the newly defined relativistic time is no longer the physical time measured with physical clocks. Thus special relativity is wrong.
The absoluteness of clock time can also be shown by physical clocks in special relativity. For example, we can use the height H of a vertical pole to represent the physical time of a clock attached to the inertial reference frame (x, y, z, t) and (x', y', z', t') respectively. If the two clocks have the same physical time observed in (x, y, z, t), we have two events:
（x1=0, y1=0, z1=T1=H, t1=t）
and
（x2=vt, y2=0, z2=T2=H, t2=t）
which are simultaneous measured with both clock time (T1 = T2 = H) and the relativistic time (t1 = t2 = t). Now let's see the two events observed in (x', y', z', t'), which can be obtained through Lorentz Transformation:
x1' = γ(x1 - vt1) = -γvt
y1' = y1 = 0
z1' = z1 = H
T1' = z1' = H
t1' = γ(t1 - vx1/c^2) = γt
x2' = γ(x2 - vt2) = γ(vt - vt) = 0
y2' = y2 = 0
z2' = z2 = H
T2' = z2' = H
t2' = γ(t2 - vx2/c^2) = γ(t - v(vt)/c^2) = γt(1 - v^2/c^2) = t/γ
That is, the two events become
（x1'=-vγt, y1'=0, z1'=T1'=H, t1'=γt)
and
（x2'=0, y2'=0, z2'=T2'=H, t2'=t/γ)
They are still simultaneous measured with clock time (T1' = T2' = H = T1 = T2), but no longer simultaneous measured with relativistic time (t1' != t2'), which means clock time is still absolute in special relativity, different from relativistic time and thus relativistic time is no longer clock time but a mathematical variable without physical meaning. Based on such a fake time, special relativity is wrong.
www.nsf.gov
Facebook
Twitter
Instagram