G
genius2007
Guest
My argument against mass and what E=mc^2 really means <br /><br />--------------------------------------------------------------------------------<br /><br />E=mc^2 the most famous equation of all time and the most correct for practical use.<br /><br />The speed of light squared provides balance between quantum and relative mechanics in that Planck time is the speed of light between Planck particles and the speed of light we see the stars by. But what is mass really?<br /><br />Planck time 5.39121 * 10^-44 seconds<br />Light 2.99792 * 10^8 m/s<br /><br />So E=mc^2 is 5.39121 * 10^-44 = m * 8.9875 *10^16<br />Thus m = 5.9986 * 10^-61<br /><br />An interesting number if you like. Assuming as I do the diameter of the proton as the boundary of the universe it then means energy equivalent to 5.9986 * 10^61ev to shatter the proton. Now to balance the equation both sides as a universe boundary is not a simple subtraction leaving zero, zero as I contend is not an option.<br /><br />To balance the equation both sides of the proton through all the protons a multiplier is required which gives:-<br />E-our quantum side * E-other quantum side = 1<br />1 = the single energy universe = 3.5983 * 10^-121<br /><br />Note the number 3.5983 * 10^-121 is very close to the measured amount of zero point quantum vibration.<br /><br />I contend one universe an energy universe fully captured and collapsing and that while it is most unlikely we would ever cause or kick start it again it is entirely plausible that the much weaker electromagnetic force could be interfered with by allowing a very low temperature reaction over a suitably large area.<br /><br />The comet that has so recently undergone a million fold increase in brightness could in fact have been just such an electromagnetic instance being large enough and not hot enough to be a barrier to the flow of energy from very high emissions from the protons within it.<br /><br />An energy universe is strange, very stable to a point and explosively and electrically